Answered

Finding the Vertex of the Pre-Image

Given the dilation rule [tex]D_{O, \frac{1}{3}}(x, y) \rightarrow \left(\frac{1}{3} x, \frac{1}{3} y\right)[/tex] and the image STUV, what are the coordinates of vertex [tex]V[/tex] of the pre-image?

A. [tex](0,0)[/tex]
B. [tex]\left(0, \frac{1}{3}\right)[/tex]
C. [tex](0,1)[/tex]
D. [tex](0,3)[/tex]



Answer :

To determine the coordinates of vertex [tex]\( V \)[/tex] of the pre-image given the dilation rule [tex]\( D_{O, 133}(x, y) \rightarrow \left(\frac{1}{3} x, \frac{1}{3} y\right) \)[/tex], we need to reverse this dilation rule. This means we need to find the original coordinates [tex]\((x, y)\)[/tex] that, when transformed by the dilation rule, result in the coordinates of vertex [tex]\( V \)[/tex] of the image.

Let's operate on each of the provided options to see which one corresponds to the given dilation rule.

### Step-by-Step Solution:

1. Option 1: [tex]\((0,0)\)[/tex]
- Applying the reverse dilation:
[tex]\[ (0, 0) \rightarrow (0 \cdot 3, 0 \cdot 3) = (0, 0) \][/tex]
- The pre-image coordinates for the image point [tex]\((0,0)\)[/tex] are [tex]\((0,0)\)[/tex].

2. Option 2: [tex]\(\left(0, \frac{1}{3}\right)\)[/tex]
- Applying the reverse dilation:
[tex]\[ \left(0, \frac{1}{3}\right) \rightarrow \left(0 \cdot 3, \frac{1}{3} \cdot 3\right) = (0, 1) \][/tex]
- The pre-image coordinates for the image point [tex]\(\left(0, \frac{1}{3}\right)\)[/tex] are [tex]\((0, 1)\)[/tex].

3. Option 3: [tex]\((0,1)\)[/tex]
- Applying the reverse dilation:
[tex]\[ (0, 1) \rightarrow (0 \cdot 3, 1 \cdot 3) = (0, 3) \][/tex]
- The pre-image coordinates for the image point [tex]\((0, 1)\)[/tex] are [tex]\((0, 3)\)[/tex].

4. Option 4: [tex]\((0,3)\)[/tex]
- Applying the reverse dilation:
[tex]\[ (0, 3) \rightarrow (0 \cdot 3, 3 \cdot 3) = (0, 9) \][/tex]
- The pre-image coordinates for the image point [tex]\((0, 3)\)[/tex] are [tex]\((0, 9)\)[/tex].

After examining all the options, the coordinates of vertex [tex]\( V \)[/tex] in the pre-image must correspond to the coordinates [tex]\((0, 3)\)[/tex] in the original image under the given dilation rule. Therefore, option 3, which is [tex]\((0, 1)\)[/tex], is the one that translates to [tex]\((0, 3)\)[/tex] in the pre-image when the dilation rule is reversed.

Thus, the coordinates of vertex [tex]\( V \)[/tex] of the pre-image are:
[tex]\[ \boxed{(0, 3)} \][/tex]

Other Questions