Factor the GCF from [tex][tex]$9x^4y - 6x^3y^2 + 3x^2y^3$[/tex][/tex].

A. [tex][tex]$3x^2y(3x^2 - 2xy + y^2)$[/tex][/tex]

B. [tex][tex]$3xy(3x^2 - 2xy + y^2)$[/tex][/tex]

C. [tex][tex]$3xy^2(3x^2 - 2xy + y^2)$[/tex][/tex]

D. [tex][tex]$3x^2y(3x^2 + 2xy + y^2)$[/tex][/tex]



Answer :

To factor the given polynomial [tex]\( 9x^4y - 6x^3y^2 + 3x^2y^3 \)[/tex], you should follow these steps:

### Step 1: Identify the Greatest Common Factor (GCF)

First, look for the greatest common factor in each term. The terms are:
- [tex]\( 9x^4y \)[/tex]
- [tex]\( 6x^3y^2 \)[/tex]
- [tex]\( 3x^2y^3 \)[/tex]

The GCF of the numerical coefficients (9, 6, and 3) is 3. For the variables, the smallest power of [tex]\( x \)[/tex] present in each term is [tex]\( x^2 \)[/tex], and the smallest power of [tex]\( y \)[/tex] is [tex]\( y \)[/tex]. Therefore, the GCF is [tex]\( 3x^2y \)[/tex].

### Step 2: Factor out the GCF

Divide each term by the GCF ([tex]\( 3x^2y \)[/tex]) and rewrite the polynomial in this factored form:
[tex]\[ 9x^4y - 6x^3y^2 + 3x^2y^3 = 3x^2y \left(\frac{9x^4y}{3x^2y} - \frac{6x^3y^2}{3x^2y} + \frac{3x^2y^3}{3x^2y}\right) \][/tex]

Simplify each term within the parentheses:
- [tex]\(\frac{9x^4y}{3x^2y} = 3x^2\)[/tex]
- [tex]\(\frac{6x^3y^2}{3x^2y} = 2xy\)[/tex]
- [tex]\(\frac{3x^2y^3}{3x^2y} = y^2\)[/tex]

### Step 3: Rewrite the Polynomial

Substitute these simplified terms back into the expression:
[tex]\[ 3x^2y \left(3x^2 - 2xy + y^2\right) \][/tex]

Thus, the factored form of the given polynomial [tex]\( 9x^4y - 6x^3y^2 + 3x^2y^3 \)[/tex] is:

[tex]\[ 3x^2y \left(3x^2 - 2xy + y^2\right) \][/tex]

### Verify the Factored Form

To ensure correctness, you can expand the factored form:
[tex]\[ 3x^2y \left(3x^2 - 2xy + y^2\right) = 3x^2y \cdot 3x^2 - 3x^2y \cdot 2xy + 3x^2y \cdot y^2 \][/tex]
[tex]\[ = 9x^4y - 6x^3y^2 + 3x^2y^3 \][/tex]

This matches the original polynomial, confirming that the factorization is correct.

### Conclusion

Hence, the correct factored form is:
[tex]\[ 3x^2y \left(3x^2 - 2xy + y^2\right) \][/tex]

The correct answer is:
[tex]\[ 3x^2 y\left(3x^2 - 2xy + y^2\right) \][/tex]

Other Questions