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How many solutions does this linear system have?

[tex]\[
\begin{array}{l}
y = 2x - 5 \\
-8x - 4y = -20
\end{array}
\][/tex]

A. One solution: [tex]\((-2.5, 0)\)[/tex]
B. One solution: [tex]\((2.5, 0)\)[/tex]
C. No solution
D. Infinite number of solutions



Answer :

Let's solve the system of linear equations step by step to determine the number of solutions:

Given equations:
[tex]\[ \begin{array}{l} y = 2x - 5 \\ -8x - 4y = -20 \end{array} \][/tex]

1. Substitute [tex]\( y \)[/tex] from the first equation into the second equation:

Since [tex]\( y = 2x - 5 \)[/tex], we can substitute this expression for [tex]\( y \)[/tex] in the second equation:
[tex]\[ -8x - 4(2x - 5) = -20 \][/tex]

2. Simplify the equation:

Distribute the [tex]\(-4\)[/tex] into the parenthesis:
[tex]\[ -8x - 8x + 20 = -20 \][/tex]

Combine like terms:
[tex]\[ -16x + 20 = -20 \][/tex]

3. Solve for [tex]\( x \)[/tex]:

Isolate [tex]\( x \)[/tex] by subtracting 20 from both sides:
[tex]\[ -16x = -40 \][/tex]

Divide both sides by [tex]\(-16\)[/tex]:
[tex]\[ x = 2.5 \][/tex]

4. Solve for [tex]\( y \)[/tex] using the first equation:

Substitute [tex]\( x = 2.5 \)[/tex] back into [tex]\( y = 2x - 5 \)[/tex]:
[tex]\[ y = 2(2.5) - 5 \][/tex]

Calculate the value of [tex]\( y \)[/tex]:
[tex]\[ y = 5 - 5 \][/tex]
[tex]\[ y = 0 \][/tex]

So the solution to the system is:
[tex]\[ (x, y) = (2.5, 0) \][/tex]

5. Determine the number of solutions:

Since we found a unique solution, the system has exactly one solution.

Therefore, the number of solutions is:

[tex]\[ \boxed{\text{one solution: } (2.5, 0)} \][/tex]

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