Answer :
Let's explore the questions step by step.
1. First Scenario: Crossing a heterozygous male (Ww) with a homozygous recessive female (ww)
The genotypes of the parents are:
- Male (Ww)
- Female (ww)
The possible offspring combinations are:
- W from male and w from female = Ww
- W from male and w from female = Ww
- w from male and w from female = ww
- w from male and w from female = ww
The offspring genotypes are:
- Ww (heterozygous)
- Ww (heterozygous)
- ww (homozygous recessive)
- ww (homozygous recessive)
The breakdown of the possible offspring is:
- 2 heterozygous (Ww)
- 2 homozygous recessive (ww)
Therefore, there is a 2 out of 4, or 0.5, chance that any given offspring will be heterozygous.
2. Second Scenario: Crossing a heterozygous (Ww) with a homozygous dominant (WW)
The genotypes of the parents are:
- Heterozygous (Ww)
- Homozygous dominant (WW)
The possible offspring combinations are:
- W from heterozygous and W from homozygous dominant = WW
- W from heterozygous and W from homozygous dominant = WW
- w from heterozygous and W from homozygous dominant = Ww
- w from heterozygous and W from homozygous dominant = Ww
The offspring genotypes are:
- WW (homozygous dominant)
- WW (homozygous dominant)
- Ww (heterozygous)
- Ww (heterozygous)
Here, there are:
- 2 homozygous dominant (WW)
- 2 heterozygous (Ww)
Therefore, the probability of producing a homozygous recessive (ww) offspring is 0 out of 4, or 0.
Final Answers:
- If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a 0.5 chance that [tex]\(50\%\)[/tex] of the offspring will be heterozygous.
- If the heterozygous, Ww, is crossed with a homozygous dominant, WW, then the probability of having a homozygous recessive offspring is 0.
1. First Scenario: Crossing a heterozygous male (Ww) with a homozygous recessive female (ww)
The genotypes of the parents are:
- Male (Ww)
- Female (ww)
The possible offspring combinations are:
- W from male and w from female = Ww
- W from male and w from female = Ww
- w from male and w from female = ww
- w from male and w from female = ww
The offspring genotypes are:
- Ww (heterozygous)
- Ww (heterozygous)
- ww (homozygous recessive)
- ww (homozygous recessive)
The breakdown of the possible offspring is:
- 2 heterozygous (Ww)
- 2 homozygous recessive (ww)
Therefore, there is a 2 out of 4, or 0.5, chance that any given offspring will be heterozygous.
2. Second Scenario: Crossing a heterozygous (Ww) with a homozygous dominant (WW)
The genotypes of the parents are:
- Heterozygous (Ww)
- Homozygous dominant (WW)
The possible offspring combinations are:
- W from heterozygous and W from homozygous dominant = WW
- W from heterozygous and W from homozygous dominant = WW
- w from heterozygous and W from homozygous dominant = Ww
- w from heterozygous and W from homozygous dominant = Ww
The offspring genotypes are:
- WW (homozygous dominant)
- WW (homozygous dominant)
- Ww (heterozygous)
- Ww (heterozygous)
Here, there are:
- 2 homozygous dominant (WW)
- 2 heterozygous (Ww)
Therefore, the probability of producing a homozygous recessive (ww) offspring is 0 out of 4, or 0.
Final Answers:
- If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a 0.5 chance that [tex]\(50\%\)[/tex] of the offspring will be heterozygous.
- If the heterozygous, Ww, is crossed with a homozygous dominant, WW, then the probability of having a homozygous recessive offspring is 0.
