If you vertically shift the square root parent function, [tex][tex]$F(x)=\sqrt{x}$[/tex][/tex], up nine units, what is the equation of the new function?

A. [tex][tex]$G(x)=\sqrt{x+9}$[/tex][/tex]
B. [tex][tex]$G(x)=\sqrt{x}$[/tex][/tex]
C. [tex][tex]$G(x)=\sqrt{x}-9$[/tex][/tex]
D. [tex][tex]$G(x)=\sqrt{x}+9$[/tex][/tex]



Answer :

To solve the problem of vertically shifting the square root parent function [tex]\( F(x) = \sqrt{x} \)[/tex] up nine units, we need to understand the effect of vertical shifts on a function.

A vertical shift involves adding or subtracting a constant value to the entire function. In this case, we want to shift [tex]\( \sqrt{x} \)[/tex] upwards by 9 units.

Let's break down the steps:

1. Understand the Vertical Shift: When we shift a function [tex]\( f(x) \)[/tex] vertically by [tex]\( k \)[/tex] units, the new function [tex]\( g(x) \)[/tex] is given by:
[tex]\[ g(x) = f(x) + k \][/tex]
If moving upwards, [tex]\( k \)[/tex] will be positive; if moving downwards, [tex]\( k \)[/tex] will be negative.

2. Apply the Shift to the Given Function:
- The original function is [tex]\( F(x) = \sqrt{x} \)[/tex].
- We want to shift this function up by 9 units, so [tex]\( k = 9 \)[/tex].

3. Form the New Function: Adding 9 to the original function gives us:
[tex]\[ G(x) = \sqrt{x} + 9 \][/tex]

So, the equation of the new function after shifting the square root function up by nine units is:

[tex]\[ G(x) = \sqrt{x} + 9 \][/tex]

Therefore, the correct answer is [tex]\( \boxed{D} \)[/tex].

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