Answer :
To find the kinetic energy of the shot, we use the formula for kinetic energy, which is given by:
[tex]\[ KE = \frac{1}{2} m v^2 \][/tex]
Let's break down the problem step by step:
1. Identify the given values:
- Mass ([tex]\(m\)[/tex]) of the shot: 4 kilograms
- Velocity ([tex]\(v\)[/tex]) of the shot: 9 meters per second
2. Substitute the given values into the kinetic energy formula:
[tex]\[ KE = \frac{1}{2} \times 4 \times (9)^2 \][/tex]
3. Calculate the square of the velocity:
[tex]\[ 9^2 = 81 \][/tex]
4. Perform the multiplication:
[tex]\[ \frac{1}{2} \times 4 \times 81 = 2 \times 81 = 162 \][/tex]
Therefore, the kinetic energy of the shot is:
[tex]\[ \boxed{162} \][/tex]
So, the shot's kinetic energy is 162 joules.
[tex]\[ KE = \frac{1}{2} m v^2 \][/tex]
Let's break down the problem step by step:
1. Identify the given values:
- Mass ([tex]\(m\)[/tex]) of the shot: 4 kilograms
- Velocity ([tex]\(v\)[/tex]) of the shot: 9 meters per second
2. Substitute the given values into the kinetic energy formula:
[tex]\[ KE = \frac{1}{2} \times 4 \times (9)^2 \][/tex]
3. Calculate the square of the velocity:
[tex]\[ 9^2 = 81 \][/tex]
4. Perform the multiplication:
[tex]\[ \frac{1}{2} \times 4 \times 81 = 2 \times 81 = 162 \][/tex]
Therefore, the kinetic energy of the shot is:
[tex]\[ \boxed{162} \][/tex]
So, the shot's kinetic energy is 162 joules.
