Answer :
To find the voltage drop across a circuit element, we use Ohm's Law, which states that the voltage ([tex]\(V\)[/tex]) across a resistor is equal to the current ([tex]\(I\)[/tex]) flowing through it multiplied by the resistance ([tex]\(R\)[/tex]) of the resistor. The formula is given as:
[tex]\[ V = I \times R \][/tex]
Here, we are provided with:
- The current, [tex]\(I = 0.050 \text{ amps} \)[/tex]
- The resistance, [tex]\(R = 100 \text{ ohms} \)[/tex]
Following the steps:
1. Write down the formula:
[tex]\[ V = I \times R \][/tex]
2. Substitute the given values:
[tex]\[ V = 0.050 \text{ amps} \times 100 \text{ ohms} \][/tex]
3. Perform the multiplication:
[tex]\[ V = 0.050 \times 100 = 5.0 \text{ volts} \][/tex]
Thus, the voltage drop across the circuit element is found to be:
[tex]\[ V = 5.0 \text{ volts} \][/tex]
Therefore, the correct answer is:
A. [tex]\( 5.0 \text{ V} \)[/tex]
[tex]\[ V = I \times R \][/tex]
Here, we are provided with:
- The current, [tex]\(I = 0.050 \text{ amps} \)[/tex]
- The resistance, [tex]\(R = 100 \text{ ohms} \)[/tex]
Following the steps:
1. Write down the formula:
[tex]\[ V = I \times R \][/tex]
2. Substitute the given values:
[tex]\[ V = 0.050 \text{ amps} \times 100 \text{ ohms} \][/tex]
3. Perform the multiplication:
[tex]\[ V = 0.050 \times 100 = 5.0 \text{ volts} \][/tex]
Thus, the voltage drop across the circuit element is found to be:
[tex]\[ V = 5.0 \text{ volts} \][/tex]
Therefore, the correct answer is:
A. [tex]\( 5.0 \text{ V} \)[/tex]
