Answer :
To solve this problem, we need to create a system of linear equations based on the information provided:
1. Martin has a total of 33 quarters and dimes. This can be expressed as:
[tex]\[ q + d = 33 \][/tex]
where [tex]\( q \)[/tex] represents the number of quarters and [tex]\( d \)[/tex] represents the number of dimes.
2. The total value of these quarters and dimes is [tex]$\$[/tex]6[tex]$. Since one quarter is worth \$[/tex]0.25 and one dime is worth \$0.10, the value equation can be written as:
[tex]\[ 0.25q + 0.1d = 6 \][/tex]
Therefore, the system of linear equations that can be used to find the number of quarters [tex]\( q \)[/tex] and the number of dimes [tex]\( d \)[/tex] is:
[tex]\[ \begin{cases} q + d = 33 \\ 0.25q + 0.1d = 6 \end{cases} \][/tex]
Hence, the correct system of linear equations is:
[tex]\[ \begin{array}{l} q + d = 33 \\ 0.25 q + 0.1 d = 6 \end{array} \][/tex]
1. Martin has a total of 33 quarters and dimes. This can be expressed as:
[tex]\[ q + d = 33 \][/tex]
where [tex]\( q \)[/tex] represents the number of quarters and [tex]\( d \)[/tex] represents the number of dimes.
2. The total value of these quarters and dimes is [tex]$\$[/tex]6[tex]$. Since one quarter is worth \$[/tex]0.25 and one dime is worth \$0.10, the value equation can be written as:
[tex]\[ 0.25q + 0.1d = 6 \][/tex]
Therefore, the system of linear equations that can be used to find the number of quarters [tex]\( q \)[/tex] and the number of dimes [tex]\( d \)[/tex] is:
[tex]\[ \begin{cases} q + d = 33 \\ 0.25q + 0.1d = 6 \end{cases} \][/tex]
Hence, the correct system of linear equations is:
[tex]\[ \begin{array}{l} q + d = 33 \\ 0.25 q + 0.1 d = 6 \end{array} \][/tex]
