Answer :
To find the kinetic energy of the shot, you can use the kinetic energy formula:
[tex]\[ KE = \frac{1}{2} mv^2 \][/tex]
where:
- [tex]\( m \)[/tex] is the mass of the shot,
- [tex]\( v \)[/tex] is the speed at which it is hurled.
Given:
- [tex]\( m = 4 \)[/tex] kilograms,
- [tex]\( v = 9 \)[/tex] meters/second,
you can plug these values into the formula.
First, calculate the velocity squared:
[tex]\[ v^2 = 9^2 = 81 \][/tex]
Next, multiply the mass by the squared velocity:
[tex]\[ m \cdot v^2 = 4 \cdot 81 = 324 \][/tex]
Finally, multiply by [tex]\( \frac{1}{2} \)[/tex]:
[tex]\[ KE = \frac{1}{2} \cdot 324 = 162 \][/tex]
Thus, the kinetic energy of the shot is [tex]\( 162 \)[/tex] joules.
[tex]\[ KE = \frac{1}{2} mv^2 \][/tex]
where:
- [tex]\( m \)[/tex] is the mass of the shot,
- [tex]\( v \)[/tex] is the speed at which it is hurled.
Given:
- [tex]\( m = 4 \)[/tex] kilograms,
- [tex]\( v = 9 \)[/tex] meters/second,
you can plug these values into the formula.
First, calculate the velocity squared:
[tex]\[ v^2 = 9^2 = 81 \][/tex]
Next, multiply the mass by the squared velocity:
[tex]\[ m \cdot v^2 = 4 \cdot 81 = 324 \][/tex]
Finally, multiply by [tex]\( \frac{1}{2} \)[/tex]:
[tex]\[ KE = \frac{1}{2} \cdot 324 = 162 \][/tex]
Thus, the kinetic energy of the shot is [tex]\( 162 \)[/tex] joules.
