The expression given does not form a complete mathematical statement or question. To make it meaningful, we can reframe it into a problem or provide context for its evaluation. Here are two possible options:

Option 1: Rewriting as an Expression to Simplify
Simplify the following expression:
[tex]\[ x^{\cosh^2 \left( \frac{x}{a} \right)} \][/tex]

Option 2: Rewriting as an Equation to Solve
Solve the following equation for [tex]\( x \)[/tex]:
[tex]\[ x^{\cosh^2 \left( \frac{x}{a} \right)} = 1 \][/tex]

Depending on the intended context, either option provides a clearer and more meaningful task.



Answer :

Let's solve the given expression step-by-step:

Given the expression:
[tex]\[ x^{\cosh^2\left(\frac{x}{a}\right)} \][/tex]

1. Identify the components:
- [tex]\( x \)[/tex]: The base of the expression
- [tex]\( \cosh\left(\frac{x}{a}\right) \)[/tex]: The hyperbolic cosine function evaluated at [tex]\(\frac{x}{a}\)[/tex]
- [tex]\( \cosh^2\left(\frac{x}{a}\right) \)[/tex]: Squaring the result of the hyperbolic cosine function

2. Understanding the Hyperbolic Cosine Function:
- The hyperbolic cosine function is defined as:
[tex]\[ \cosh(y) = \frac{e^y + e^{-y}}{2} \][/tex]
- In this problem, the variable [tex]\( y \)[/tex] is replaced with [tex]\(\frac{x}{a}\)[/tex], so we have:
[tex]\[ \cosh\left(\frac{x}{a}\right) = \frac{e^{\frac{x}{a}} + e^{-\frac{x}{a}}}{2} \][/tex]

3. Square of Hyperbolic Cosine Function:
- Squaring the hyperbolic cosine function:
[tex]\[ \cosh^2\left(\frac{x}{a}\right) = \left(\frac{e^{\frac{x}{a}} + e^{-\frac{x}{a}}}{2}\right)^2 \][/tex]
Simplifying the square:
[tex]\[ \cosh^2\left(\frac{x}{a}\right) = \left(\frac{e^{\frac{x}{a}} + e^{-\frac{x}{a}}}{2}\right) \times \left(\frac{e^{\frac{x}{a}} + e^{-\frac{x}{a}}}{2}\right) \][/tex]
[tex]\[ \cosh^2\left(\frac{x}{a}\right) = \frac{(e^{\frac{x}{a}} + e^{-\frac{x}{a}})^2}{4} \][/tex]
Expanding the numerator:
[tex]\[ \cosh^2\left(\frac{x}{a}\right) = \frac{e^{\frac{2x}{a}} + 2 + e^{-\frac{2x}{a}}}{4} \][/tex]

4. Final Expression:
- Substitute the squared hyperbolic cosine back into the original expression:
[tex]\[ x^{\cosh^2\left(\frac{x}{a}\right)} = x^{\frac{e^{\frac{2x}{a}} + 2 + e^{-\frac{2x}{a}}}{4}} \][/tex]

However, recognizing the structure and arriving directly to the answer, we arrive at the simplified form:
[tex]\[ x^{\left(\cosh\left(\frac{x}{a}\right)\right)^2} \][/tex]

Thus, the final expression we were asked to find is:
[tex]\[ x^{\cosh^2 \left(\frac{x}{a}\right)} \][/tex]

This process breaks down the components of the given expression step-by-step to understand the underlying functions and operations.

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