Answered

Given the chemical equation:

[tex]\[2 \text{MnCl}_2 + 8 \text{H}_2\text{O} + \dots\][/tex]

Calculate the amount of water produced.

Use the equation below to perform the calculation:

[tex]\[3.45 \, \text{mol} \, \text{KMnO}_4 \times \frac{8 \, \text{mol} \, \text{H}_2\text{O}}{2 \, \text{mol} \, \text{KMnO}_4}\][/tex]

Did you set up the equation correctly?

A. Yes, and I got the correct answer.
B. Yes, but I got the wrong answer because I made a mathematical error.
C. No, I did not set up the equation correctly.



Answer :

GinnyAnswer
Let's work through this problem step-by-step to find out how many moles of [tex]\( \text{H}_2\text{O} \)[/tex] are produced when 3.45 moles of [tex]\( \text{KMnO}_4 \)[/tex] are used.

First, let's analyze the equation given:
[tex]\[ 3.45 \, \text{mol} \, \text{KMnO}_4 \times \frac{8 \, \text{mol} \, \text{H}_2\text{O}}{2 \, \text{mol} \, \text{KMnO}_4} \][/tex]

This equation indicates that for every 2 moles of [tex]\( \text{KMnO}_4 \)[/tex], 8 moles of [tex]\( \text{H}_2\text{O} \)[/tex] are produced. To proceed, follow these steps:

### Step 1: Determine the mole ratio between [tex]\( \text{KMnO}_4 \)[/tex] and [tex]\( \text{H}_2\text{O} \)[/tex]
The stoichiometric ratio provided is:
[tex]\[ \frac{8 \, \text{mol} \, \text{H}_2\text{O}}{2 \, \text{mol} \, \text{KMnO}_4} \][/tex]

This ratio can be simplified:
[tex]\[ \frac{8}{2} = 4 \][/tex]

### Step 2: Use the mole ratio to find the number of moles of [tex]\( \text{H}_2\text{O} \)[/tex] produced
Next, multiply the initial moles of [tex]\( \text{KMnO}_4 \)[/tex] by the simplified ratio:
[tex]\[ 3.45 \, \text{mol} \, \text{KMnO}_4 \times 4 = 13.8 \, \text{mol} \, \text{H}_2\text{O} \][/tex]

### Conclusion
Thus, using 3.45 moles of [tex]\( \text{KMnO}_4 \)[/tex] will produce 13.8 moles of [tex]\( \text{H}_2\text{O} \)[/tex].

Other Questions