Answered

A car battery produces electrical energy with the following chemical reaction:
[tex]\[ Pb + PbO_2 + 2H_2SO_4 \rightarrow 2PbSO_4 + 2H_2O \][/tex]

What is the mole ratio of [tex]\( PbO_2 \)[/tex] to water?

[tex]\[ PbO_2 : H_2O = 1 : \square \][/tex]



Answer :

GinnyAnswer
To determine the mole ratio of [tex]\(\text{PbO}_2\)[/tex] (lead dioxide) to [tex]\(\text{H}_2\text{O}\)[/tex] (water) in the given chemical reaction, follow these steps:

1. Identify the given balanced chemical equation:
[tex]\[ \text{Pb} + \text{PbO}_2 + 2\text{H}_2\text{SO}_4 \rightarrow 2\text{PbSO}_4 + 2\text{H}_2\text{O} \][/tex]

2. Determine the coefficients of the reactants and products from the balanced equation:
- Notice the coefficient for [tex]\(\text{PbO}_2\)[/tex] is [tex]\(1\)[/tex].
- Notice the coefficient for [tex]\(\text{H}_2\text{O}\)[/tex] is [tex]\(2\)[/tex].

3. Establish the mole ratio based on the coefficients:
- For every 1 mole of [tex]\(\text{PbO}_2\)[/tex] consumed, 2 moles of [tex]\(\text{H}_2\text{O}\)[/tex] are produced.
- This can be represented as:
[tex]\[ \text{PbO}_2 : \text{H}_2\text{O} = 1 : 2 \][/tex]

4. Write the mole ratio explicitly:
[tex]\[ \text{PbO}_2 : \text{H}_2\text{O} = 1 : 2 \][/tex]

Therefore, the mole ratio of [tex]\(\text{PbO}_2\)[/tex] to [tex]\(\text{H}_2\text{O}\)[/tex] is [tex]\(1 : 2\)[/tex].

So, the final answer is:
[tex]\[ PbO_2 : H_2O = 1 : 2 \][/tex]

Other Questions