Answer :
Sure, let's solve the problem step-by-step to find the area under the curve [tex]\( f(x) = \frac{12(\ln x)^5}{x} \)[/tex] over the interval [tex]\([1, 3]\)[/tex].
### Step 1: Understand the function
We have the function:
[tex]\[ f(x) = \frac{12(\ln x)^5}{x} \][/tex]
### Step 2: Set up the definite integral
To find the area under this curve over the interval [tex]\([1, 3]\)[/tex], we set up the definite integral:
[tex]\[ \int_{1}^{3} \frac{12(\ln x)^5}{x} \, dx \][/tex]
### Step 3: Evaluate the integral
Evaluating this integral involves integrating the given function within the specified limits. This is generally done using techniques like substitution, integration by parts, or numerical methods. For complex integrals, numerical integration methods or computational tools might be more appropriate.
### Step 4: Compute the result
After performing the intended calculations, we find the result:
[tex]\[ \int_{1}^{3} \frac{12(\ln x)^5}{x} \, dx \approx 3.51638736653023 \][/tex]
So, the area under the curve from [tex]\(x = 1\)[/tex] to [tex]\(x = 3\)[/tex] is approximately [tex]\(3.51638736653023\)[/tex].
### Step 5: Address the error margin
When integrating, especially numerically, there may be a small margin of error. In our calculations, the error is:
[tex]\[ \text{Error} \approx 2.299524311945404 \times 10^{-10} \][/tex]
### Conclusion
Therefore, the area under the curve [tex]\( f(x) = \frac{12(\ln x)^5}{x} \)[/tex] from [tex]\(x = 1\)[/tex] to [tex]\(x = 3\)[/tex] is approximately [tex]\(3.51638736653023\)[/tex].
### Step 1: Understand the function
We have the function:
[tex]\[ f(x) = \frac{12(\ln x)^5}{x} \][/tex]
### Step 2: Set up the definite integral
To find the area under this curve over the interval [tex]\([1, 3]\)[/tex], we set up the definite integral:
[tex]\[ \int_{1}^{3} \frac{12(\ln x)^5}{x} \, dx \][/tex]
### Step 3: Evaluate the integral
Evaluating this integral involves integrating the given function within the specified limits. This is generally done using techniques like substitution, integration by parts, or numerical methods. For complex integrals, numerical integration methods or computational tools might be more appropriate.
### Step 4: Compute the result
After performing the intended calculations, we find the result:
[tex]\[ \int_{1}^{3} \frac{12(\ln x)^5}{x} \, dx \approx 3.51638736653023 \][/tex]
So, the area under the curve from [tex]\(x = 1\)[/tex] to [tex]\(x = 3\)[/tex] is approximately [tex]\(3.51638736653023\)[/tex].
### Step 5: Address the error margin
When integrating, especially numerically, there may be a small margin of error. In our calculations, the error is:
[tex]\[ \text{Error} \approx 2.299524311945404 \times 10^{-10} \][/tex]
### Conclusion
Therefore, the area under the curve [tex]\( f(x) = \frac{12(\ln x)^5}{x} \)[/tex] from [tex]\(x = 1\)[/tex] to [tex]\(x = 3\)[/tex] is approximately [tex]\(3.51638736653023\)[/tex].
