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[tex]$4 \quad 1 \quad 6 \longdiv { 1 2 , 8 9 6 }$[/tex]
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Response:
Perform the division:
[tex]\[ 4 \quad 1 \quad 6 \longdiv { 1 2 , 8 9 6 } \][/tex]



Answer :

GinnyAnswer
To solve the division problem [tex]\( 12896 \div 416 \)[/tex], we'll find the quotient and remainder step-by-step.

1. Set up the division: We are dividing 12896 by 416.

2. Determine how many times 416 fits into the leading part of 12896:
- Look at the first three digits, which are 128. Since 416 is larger than 128, we consider the first four digits, 1289.

3. Estimate how many times 416 fits into 1289:
- We estimate: if we try 3, it would be [tex]\( 3 \times 416 = 1248 \)[/tex].

4. Subtract the result from the leading part:
- Subtract 1248 from 1289: [tex]\( 1289 - 1248 = 41 \)[/tex].

5. Bring down the next digit:
- We bring down the next digit from 12896, which is 6, to get 416.

6. Determine how many times 416 fits into 416:
- It fits exactly once as [tex]\( 1 \times 416 = 416 \)[/tex].

7. Subtract the result:
- Subtract 416 from 416: [tex]\( 416 - 416 = 0 \)[/tex].

8. End of the process:
- There are no more digits to bring down, so the division process is complete.

The quotient of the division is 31 and the remainder is 0.

So, [tex]\( 12896 \div 416 \)[/tex] results in a quotient of 31 and a remainder of 0.

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