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Calculate the work done by friction using the following data:

\begin{tabular}{|l|l|l|l|l|}
\hline
& Mass [tex]$(g)$[/tex] & Distance [tex]$(m)$[/tex] & Force [tex]$(N)$[/tex] & Work Done by Friction (J) \\
\hline
Car going up the incline & 100 & 39 & 0.063 & 2.457 \\
\hline
Car going down the incline & 70 & 39 & 0.2309 & [tex]$?$[/tex] \\
\hline
\end{tabular}

The relationship between force and distance determines the work done by friction [tex]$\left(W_{f}\right)$[/tex]:

[tex]\[ W_{f} = f \cdot d \][/tex]

Where:
[tex]\[ W_{f} \text{ is the work done by friction} \][/tex]
[tex]\[ f \text{ is the force} \][/tex]
[tex]\[ d \text{ is the distance} \][/tex]

Question:
How much work done by friction was exerted on the car as it moved down the inclined plane? You may use a calculator.

A. 2.457
B. 9.005
C. 11.46
D. 16.16



Answer :

GinnyAnswer
To determine how much work done by friction was exerted on the car as it moved down the inclined plane, let's follow a step-by-step process using the given data and the formula for work done by friction:

Step 1: Write down the formula for work done by friction:
[tex]\[ W_f = f \times d \][/tex]
where:
- [tex]\( W_f \)[/tex] is the work done by friction,
- [tex]\( f \)[/tex] is the force,
- [tex]\( d \)[/tex] is the distance.

Step 2: Identify the given values:
- The force [tex]\( f \)[/tex] acting on the car going down the incline is [tex]\( 0.2309 \)[/tex] Newtons.
- The distance [tex]\( d \)[/tex] the car travels is [tex]\( 39 \)[/tex] meters.

Step 3: Plug these values into the formula:
[tex]\[ W_f = 0.2309 \, \text{N} \times 39 \, \text{m} \][/tex]

Step 4: Calculate the work done by friction:
[tex]\[ W_f = 9.0051 \][/tex]

Therefore, the work done by friction exerted on the car as it moved down the inclined plane is [tex]\( 9.0051 \)[/tex] Joules.

The correct answer is:
(B) 9.005

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