Let's write trinomial expressions of the form [tex]ax + by + c[/tex], where [tex]a[/tex], [tex]b[/tex], and [tex]c[/tex] are integers.

Find the sum and difference of your expressions.



Answer :

Certainly! Let's consider two trinomial expressions of the form [tex]\( ax + by + c \)[/tex].

We define the first trinomial expression as:
[tex]\[ \text{Expression 1: } 2x + 5y + 7 \][/tex]

And the second trinomial expression as:
[tex]\[ \text{Expression 2: } 3x + y + 4 \][/tex]

Now, let's find the sum of these two trinomial expressions. We add the corresponding coefficients of [tex]\( x \)[/tex], [tex]\( y \)[/tex], and the constant terms.

1. Add the coefficients of [tex]\( x \)[/tex]:
[tex]\[ 2 + 3 = 5 \][/tex]

2. Add the coefficients of [tex]\( y \)[/tex]:
[tex]\[ 5 + 1 = 6 \][/tex]

3. Add the constant terms:
[tex]\[ 7 + 4 = 11 \][/tex]

So, the sum of the two trinomial expressions is:
[tex]\[ (2x + 5y + 7) + (3x + y + 4) = 5x + 6y + 11 \][/tex]

Next, let's find the difference of these two trinomial expressions. We subtract the corresponding coefficients of [tex]\( x \)[/tex], [tex]\( y \)[/tex], and the constant terms of the second expression from the first.

1. Subtract the coefficients of [tex]\( x \)[/tex]:
[tex]\[ 2 - 3 = -1 \][/tex]

2. Subtract the coefficients of [tex]\( y \)[/tex]:
[tex]\[ 5 - 1 = 4 \][/tex]

3. Subtract the constant terms:
[tex]\[ 7 - 4 = 3 \][/tex]

So, the difference of the two trinomial expressions is:
[tex]\[ (2x + 5y + 7) - (3x + y + 4) = -x + 4y + 3 \][/tex]

In summary:
- The sum of the trinomials [tex]\( 2x + 5y + 7 \)[/tex] and [tex]\( 3x + y + 4 \)[/tex] is [tex]\( 5x + 6y + 11 \)[/tex].
- The difference of the trinomials [tex]\( 2x + 5y + 7 \)[/tex] and [tex]\( 3x + y + 4 \)[/tex] is [tex]\( -x + 4y + 3 \)[/tex].

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