Answer :
To solve this problem, we need to determine if Robert met at least 75% of the recommended daily allowance for vitamins B12, C, and E given his meal intake. Let's go through the calculation step-by-step.
1. Recommended daily intake for each vitamin:
- Vitamin B12: [tex]\( 2.4 \mu g \)[/tex]
- Vitamin C: [tex]\( 75 mg \)[/tex]
- Vitamin E: [tex]\( 15 mg \)[/tex]
2. Nutrient content of each food item in the meal:
- Salmon fillet (124 g):
- Vitamin B12: [tex]\( 5.87 \mu g \)[/tex]
- Vitamin C: [tex]\( 0.0 mg \)[/tex]
- Vitamin E: [tex]\( 0.60 mg \)[/tex]
- Boiled green beans (1 cup):
- Vitamin B12: [tex]\( 0.0 \mu g \)[/tex]
- Vitamin C: [tex]\( 12.1 mg \)[/tex]
- Vitamin E: [tex]\( 0.57 mg \)[/tex]
- Strawberries, sliced (1/2 cup):
- Vitamin B12: [tex]\( 0.0 \mu g \)[/tex]
- Vitamin C: [tex]\( 49.0 mg \)[/tex]
- Vitamin E: [tex]\( 0.42 mg \)[/tex]
3. Calculate total nutrient intake for each vitamin:
- Total Vitamin B12: [tex]\( 5.87 \mu g + 0.0 \mu g + 0.0 \mu g = 5.87 \mu g \)[/tex]
- Total Vitamin C: [tex]\( 0.0 mg + 12.1 mg + 49.0 mg = 61.1 mg \)[/tex]
- Total Vitamin E: [tex]\( 0.60 mg + 0.57 mg + 0.42 mg = 1.59 mg \)[/tex]
4. Calculate the percent of recommended intake met for each vitamin:
- Percent of Vitamin B12: [tex]\( \frac{5.87 \mu g}{2.4 \mu g} \times 100 \approx 244.58\% \)[/tex]
- Percent of Vitamin C: [tex]\( \frac{61.1 mg}{75 mg} \times 100 \approx 81.47\% \)[/tex]
- Percent of Vitamin E: [tex]\( \frac{1.59 mg}{15 mg} \times 100 \approx 10.6\% \)[/tex]
5. Determine which vitamins meet at least 75% of the recommended intake:
- Vitamin B12: [tex]\( 244.58\% \)[/tex] (meets at least 75%)
- Vitamin C: [tex]\( 81.47\% \)[/tex] (meets at least 75%)
- Vitamin E: [tex]\( 10.6\% \)[/tex] (does not meet 75%)
6. Conclusion:
Robert met at least 75% of the recommended daily allowance for Vitamins B12 and C only.
Hence, the correct answer is:
B. vitamin B12 and vitamin C only
1. Recommended daily intake for each vitamin:
- Vitamin B12: [tex]\( 2.4 \mu g \)[/tex]
- Vitamin C: [tex]\( 75 mg \)[/tex]
- Vitamin E: [tex]\( 15 mg \)[/tex]
2. Nutrient content of each food item in the meal:
- Salmon fillet (124 g):
- Vitamin B12: [tex]\( 5.87 \mu g \)[/tex]
- Vitamin C: [tex]\( 0.0 mg \)[/tex]
- Vitamin E: [tex]\( 0.60 mg \)[/tex]
- Boiled green beans (1 cup):
- Vitamin B12: [tex]\( 0.0 \mu g \)[/tex]
- Vitamin C: [tex]\( 12.1 mg \)[/tex]
- Vitamin E: [tex]\( 0.57 mg \)[/tex]
- Strawberries, sliced (1/2 cup):
- Vitamin B12: [tex]\( 0.0 \mu g \)[/tex]
- Vitamin C: [tex]\( 49.0 mg \)[/tex]
- Vitamin E: [tex]\( 0.42 mg \)[/tex]
3. Calculate total nutrient intake for each vitamin:
- Total Vitamin B12: [tex]\( 5.87 \mu g + 0.0 \mu g + 0.0 \mu g = 5.87 \mu g \)[/tex]
- Total Vitamin C: [tex]\( 0.0 mg + 12.1 mg + 49.0 mg = 61.1 mg \)[/tex]
- Total Vitamin E: [tex]\( 0.60 mg + 0.57 mg + 0.42 mg = 1.59 mg \)[/tex]
4. Calculate the percent of recommended intake met for each vitamin:
- Percent of Vitamin B12: [tex]\( \frac{5.87 \mu g}{2.4 \mu g} \times 100 \approx 244.58\% \)[/tex]
- Percent of Vitamin C: [tex]\( \frac{61.1 mg}{75 mg} \times 100 \approx 81.47\% \)[/tex]
- Percent of Vitamin E: [tex]\( \frac{1.59 mg}{15 mg} \times 100 \approx 10.6\% \)[/tex]
5. Determine which vitamins meet at least 75% of the recommended intake:
- Vitamin B12: [tex]\( 244.58\% \)[/tex] (meets at least 75%)
- Vitamin C: [tex]\( 81.47\% \)[/tex] (meets at least 75%)
- Vitamin E: [tex]\( 10.6\% \)[/tex] (does not meet 75%)
6. Conclusion:
Robert met at least 75% of the recommended daily allowance for Vitamins B12 and C only.
Hence, the correct answer is:
B. vitamin B12 and vitamin C only
