Answer :
Certainly! Let's fill in the table based on the properties of the subatomic particles.
1. Proton:
- Charge: [tex]\( +1 \)[/tex]
- Location: Nucleus
- Approximate mass (amu): The approximate mass of a proton is [tex]\( 1 \)[/tex] amu.
2. Neutron:
- Charge: [tex]\( 0 \)[/tex]
- Location: Nucleus
- Approximate mass (amu): The approximate mass of a neutron is [tex]\( 1 \)[/tex] amu.
3. Electron:
- Charge: [tex]\( -1 \)[/tex]
- Location: Orbitals
- Approximate mass (amu): The approximate mass of an electron is [tex]\( 0.0005 \)[/tex] amu.
So the completed table will be:
\begin{tabular}{|l|l|l|l|}
\hline
Particle & Charge & Location & \begin{tabular}{l}
Approximate \\
mass (amu)
\end{tabular} \\
\hline
Proton & [tex]\( +1 \)[/tex] & Nucleus & [tex]\( 1 \)[/tex] \\
\hline
Neutron & [tex]\( 0 \)[/tex] & Nucleus & [tex]\( 1 \)[/tex] \\
\hline
Electron & [tex]\( -1 \)[/tex] & Orbitals & [tex]\( 0.0005 \)[/tex] \\
\hline
\end{tabular}
1. Proton:
- Charge: [tex]\( +1 \)[/tex]
- Location: Nucleus
- Approximate mass (amu): The approximate mass of a proton is [tex]\( 1 \)[/tex] amu.
2. Neutron:
- Charge: [tex]\( 0 \)[/tex]
- Location: Nucleus
- Approximate mass (amu): The approximate mass of a neutron is [tex]\( 1 \)[/tex] amu.
3. Electron:
- Charge: [tex]\( -1 \)[/tex]
- Location: Orbitals
- Approximate mass (amu): The approximate mass of an electron is [tex]\( 0.0005 \)[/tex] amu.
So the completed table will be:
\begin{tabular}{|l|l|l|l|}
\hline
Particle & Charge & Location & \begin{tabular}{l}
Approximate \\
mass (amu)
\end{tabular} \\
\hline
Proton & [tex]\( +1 \)[/tex] & Nucleus & [tex]\( 1 \)[/tex] \\
\hline
Neutron & [tex]\( 0 \)[/tex] & Nucleus & [tex]\( 1 \)[/tex] \\
\hline
Electron & [tex]\( -1 \)[/tex] & Orbitals & [tex]\( 0.0005 \)[/tex] \\
\hline
\end{tabular}