A satellite launch rocket has a cylindrical fuel tank. The fuel tank can hold [tex][tex]$V$[/tex][/tex] cubic meters of fuel. If the tank measures [tex][tex]$d$[/tex][/tex] meters across, what is the height of the tank in meters?

A. [tex]\frac{2 V}{x d^2}[/tex]
B. [tex]\frac{4 V}{e^1}[/tex]
C. [tex]\frac{V}{\pi \pi^2}[/tex]
D. [tex]\frac{4 V}{\pi d^2}[/tex]
E. [tex]\frac{8 V}{\pi d^2}[/tex]



Answer :

To determine the height of a cylindrical fuel tank that can hold [tex]\( V \)[/tex] cubic meters of fuel and has a diameter [tex]\( d \)[/tex] meters, we start by using the formula for the volume of a cylinder:

[tex]\[ V = \pi r^2 h \][/tex]

Here, [tex]\( V \)[/tex] is the volume, [tex]\( r \)[/tex] is the radius of the base, and [tex]\( h \)[/tex] is the height.

Given that the diameter [tex]\( d \)[/tex] of the cylinder is [tex]\( d \)[/tex] meters, the radius [tex]\( r \)[/tex] can be expressed as:

[tex]\[ r = \frac{d}{2} \][/tex]

Substitute this expression for [tex]\( r \)[/tex] into the volume formula:

[tex]\[ V = \pi \left(\frac{d}{2}\right)^2 h \][/tex]

Simplify the term inside the parentheses:

[tex]\[ \left(\frac{d}{2}\right)^2 = \frac{d^2}{4} \][/tex]

So, the formula for the volume becomes:

[tex]\[ V = \pi \cdot \frac{d^2}{4} \cdot h \][/tex]

To isolate [tex]\( h \)[/tex], rearrange the equation to solve for [tex]\( h \)[/tex]:

[tex]\[ h = \frac{4V}{\pi d^2} \][/tex]

Here, [tex]\( h \)[/tex] is expressed in terms of the volume [tex]\( V \)[/tex], the diameter [tex]\( d \)[/tex], and [tex]\(\pi\)[/tex]. According to the multiple-choice options given in the question, the correct answer is:

[tex]\[ D. \frac{4 V}{\pi d^2} \][/tex]

This indicates that the height of the tank is:

[tex]\[ h = \frac{4 V}{\pi d^2} \][/tex]

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