The [tex]$n$[/tex]th term of a sequence is [tex]$8 - 6n$[/tex].

(b) Is -58 a term of this sequence? You must show how you get your answer.



Answer :

To determine if -58 is a term in the sequence whose [tex]$n$[/tex]th term is given by [tex]\( 8 - 6n \)[/tex], we need to find an integer value of [tex]\( n \)[/tex] such that the term in the sequence equals -58. Let's follow these steps:

1. Set the [tex]$n$[/tex]th term equal to -58:
[tex]\[ 8 - 6n = -58 \][/tex]

2. Solve for [tex]\( n \)[/tex].

First, isolate the term [tex]\(-6n\)[/tex] by subtracting 8 from both sides of the equation:
[tex]\[ -6n = -58 - 8 \][/tex]

Simplify the right-hand side:
[tex]\[ -6n = -66 \][/tex]

3. Next, solve for [tex]\( n \)[/tex] by dividing both sides by -6:
[tex]\[ n = \frac{-66}{-6} \][/tex]

Simplify the division:
[tex]\[ n = 11 \][/tex]

4. Verify if [tex]\( n = 11 \)[/tex] is an integer. Indeed, [tex]\( n = 11 \)[/tex] is a positive integer.

Therefore, since [tex]\( n = 11 \)[/tex] is an integer, -58 is a term of the sequence [tex]\( 8 - 6n \)[/tex].

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