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The dimensions and number of animals are given for different corrals.

\begin{tabular}{|l|l|l|l|}
\hline
Corral & \multicolumn{1}{|c|}{Length} & \multicolumn{1}{|c|}{Width} & \multicolumn{1}{|c|}{Number of Animals} \\
\hline
1 & 50 meters & 40 meters & 110 \\
\hline
2 & 60 meters & 35 meters & 115 \\
\hline
3 & 55 meters & 45 meters & 125 \\
\hline
4 & 65 meters & 40 meters & 130 \\
\hline
\end{tabular}

The population constraints state that each corral should have at least 20 square meters for each animal.

Which corral meets this requirement?
A. Corral 1
B. Corral 2
C. Corral 3
D. Corral 4



Answer :

GinnyAnswer
Let's analyze whether each corral meets the requirement that each animal should have at least 20 square meters of space.

First, we'll find the area for each corral:
1. Corral 1:
- Length: 50 meters
- Width: 40 meters
- Area = Length × Width = 50 × 40 = 2000 square meters
- Number of Animals = 110
- Area per Animal = Total Area / Number of Animals = 2000 / 110 ≈ 18.18 square meters/animal

2. Corral 2:
- Length: 60 meters
- Width: 35 meters
- Area = Length × Width = 60 × 35 = 2100 square meters
- Number of Animals = 115
- Area per Animal = Total Area / Number of Animals = 2100 / 115 ≈ 18.26 square meters/animal

3. Corral 3:
- Length: 55 meters
- Width: 45 meters
- Area = Length × Width = 55 × 45 = 2475 square meters
- Number of Animals = 125
- Area per Animal = Total Area / Number of Animals = 2475 / 125 = 19.8 square meters/animal

4. Corral 4:
- Length: 65 meters
- Width: 40 meters
- Area = Length × Width = 65 × 40 = 2600 square meters
- Number of Animals = 130
- Area per Animal = Total Area / Number of Animals = 2600 / 130 = 20.0 square meters/animal

Now, let’s compare the area per animal for each corral to the required minimum of 20 square meters:
- Corral 1: 18.18 < 20 (Does not meet the requirement)
- Corral 2: 18.26 < 20 (Does not meet the requirement)
- Corral 3: 19.8 < 20 (Does not meet the requirement)
- Corral 4: 20.0 = 20 (Meets the requirement)

Therefore, the only corral that meets the requirement is:

B. Corral 4

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