Select the correct answer.

Graph the following system of inequalities.
[tex]\ \textless \ br/\ \textgreater \ \begin{array}{l}\ \textless \ br/\ \textgreater \ y \leq \frac{1}{3} x - 2 \\\ \textless \ br/\ \textgreater \ x \ \textless \ 4\ \textless \ br/\ \textgreater \ \end{array}\ \textless \ br/\ \textgreater \ [/tex]

Certainly! Let's graph the given system of inequalities step-by-step:

### Given Inequalities:
1. [tex]$ y \leq \frac{1}{3}x - 2 $[/tex]
2. [tex]$ x < 4 $[/tex]

### Step 1: Graph the Boundary Line for the First Inequality
Begin by graphing the line [tex]$ y = \frac{1}{3}x - 2 $[/tex]. This line serves as the boundary for the inequality [tex]$ y \leq \frac{1}{3}x - 2 $[/tex].

#### Intercepts:

- Y-intercept: When [tex]$ x = 0 $[/tex]:
[tex]\[ y = \frac{1}{3}(0) - 2 = -2 \][/tex]
So, the y-intercept is [tex]$ (0, -2) $[/tex].

- X-intercept: When [tex]$ y = 0 $[/tex]:
[tex]\[ 0 = \frac{1}{3}x - 2 \implies \frac{1}{3}x = 2 \implies x = 6 \][/tex]
So, the x-intercept is [tex]$ (6, 0) $[/tex].

#### Drawing the Line
Plot the points [tex]$ (0, -2) $[/tex] and [tex]$ (6, 0) $[/tex] on a coordinate plane, then draw the line connecting these points. This line has a slope of [tex]$ \frac{1}{3} $[/tex].

Since the inequality is [tex]$ y \leq \frac{1}{3}x - 2 $[/tex], shade the region below and on the line.

### Step 2: Graph the Inequality [tex]$ x < 4 $[/tex]

Draw a vertical dashed line at [tex]$ x = 4 $[/tex]. A dashed line is used because the inequality is strict (it doesn't include [tex]$ x = 4 $[/tex]).

Shade to the left of this line because the inequality specifies [tex]$ x < 4 $[/tex].

### Step 3: Identify the Solution Region
The solution to this system of inequalities is the region where the shaded areas overlap:

- Below and on the line [tex]$ y = \frac{1}{3}x - 2 $[/tex]
- To the left of [tex]$ x = 4 $[/tex]

### Graph Summary
1. Plot the line [tex]$ y = \frac{1}{3}x - 2 $[/tex]. Shade below this line (including the line since it is [tex]$ \leq $[/tex]).
2. Draw a dashed vertical line at [tex]$ x = 4 $[/tex]. Shade to the left of this line (not including the line itself).
3. The overlapping shaded region of these two inequalities is the solution to the system.

### Graph:

1. Boundary: Line [tex]$ y = \frac{1}{3}x - 2 $[/tex]
- Y-intercept at [tex]$ (0, -2) $[/tex]
- X-intercept at [tex]$ (6, 0) $[/tex]

2. Vertical Boundary: Dashed line at [tex]$ x = 4 $[/tex]

3. Shading:
- Below the line [tex]$ y = \frac{1}{3}x - 2 $[/tex]
- To the left of [tex]$ x = 4 $[/tex]

This overlapping region shows all possible [tex]$ (x, y) $[/tex] pairs that satisfy both inequalities.