Answered

Factor completely, then place the factors in the proper location on the grid.

[tex]\[ 3y^4 - 2y^2 - 5 \][/tex]

[tex]\[
\square
\][/tex]

\begin{tabular}{|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|}
\hline
1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 0 & ( & - & - & + & 1 & ) & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 6 & [tex]$x$[/tex] & [tex]$x$[/tex] & [tex]$y$[/tex] & [tex]$z$[/tex] \\
\hline
\end{tabular}



Answer :

GinnyAnswer
To factor the polynomial [tex]\( 3y^4 - 2y^2 - 5 \)[/tex] completely, we will break down the expression into its simplest factors.

Let's begin by factoring it step-by-step:

1. Identify the polynomial:
[tex]\( 3y^4 - 2y^2 - 5 \)[/tex]

2. Set it in standard polynomial form:
This polynomial is already in standard form: [tex]\( ay^4 + by^2 + c \)[/tex]

3. Factor the polynomial:
[tex]\[ 3y^4 - 2y^2 - 5 \][/tex]

After factoring, we get:
[tex]\[ (y^2 + 1)(3y^2 - 5) \][/tex]

Therefore, the completely factored form of [tex]\( 3y^4 - 2y^2 - 5 \)[/tex] is:
[tex]\[ (y^2 + 1)(3y^2 - 5) \][/tex]

Now, place the factors in the proper locations on the grid:
1. Drag (, "y", "^", "2", "+", "1", ")" to form the factor [tex]\( (y^2 + 1) \)[/tex]
2. Drag (, "3", "y", "^", "2", "-", "5", ")" to form the factor [tex]\( (3y^2 - 5) \)[/tex]

So, the input on the grid should appear as:

[tex]\[ \boxed{(y^2 + 1)(3y^2 - 5)} \][/tex]

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