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Complete the following cumulative frequency table.

[tex]\[
\begin{tabular}{|c|c|c|}
\hline
Class mark & Frequency & Less than type Frequency \\
\hline
[tex]$0-10$[/tex] & 3 & 3 \\
[tex]$10-20$[/tex] & 15 & [tex]$3+15=\square$[/tex] \\
[tex]$20-30$[/tex] & 20 & [tex]$18+20=38$[/tex] \\
[tex]$30-40$[/tex] & 12 & [tex]$38+12=50$[/tex] \\
\hline
Total & [tex]$N=\square 0$[/tex] & \\
\hline
\end{tabular}
\][/tex]



Answer :

GinnyAnswer
Sure! Let's complete the cumulative frequency table step by step.

We'll start with the given data and fill in the missing parts:

1. For the class mark "0-10":
- Frequency: 3
- Less than type Frequency: 3 (This is directly given)

2. For the class mark "10-20":
- Frequency: 15
- Less than type Frequency: We know the previous cumulative frequency is 3.
[tex]\[ \text{Cumulative Frequency} = 3 + 15 = 18 \][/tex]
So, the less than type Frequency is 18.

3. For the class mark "20-30":
- Frequency: 20
- Less than type Frequency: We know the previous cumulative frequency is 18.
[tex]\[ \text{Cumulative Frequency} = 18 + 20 = 38 \][/tex]
So, the less than type Frequency is 38.

4. For the class mark "30-40":
- Frequency: 12
- Less than type Frequency: We know the previous cumulative frequency is 38.
[tex]\[ \text{Cumulative Frequency} = 38 + 12 = 50 \][/tex]
So, the less than type Frequency is 50.

Finally, we sum up all the frequencies to get the total frequency \( N \):
[tex]\[ N = 3 + 15 + 20 + 12 = 50 \][/tex]

Here is the completed table:

[tex]\[ \begin{array}{|c|c|c|} \hline \text{Class mark} & \text{Frequency} & \text{Less than type Frequency} \\ \hline 0-10 & 3 & 3 \\ 10-20 & 15 & 18 \\ 20-30 & 20 & 38 \\ 30-40 & 12 & 50 \\ \hline \text{Total} & N=50 & \\ \hline \end{array} \][/tex]

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