\begin{tabular}{|c|c|c|c|c|c|}
\hline
[tex]$x$[/tex] & 1 & 2 & 3 & 4 & 5 \\
\hline
[tex]$y$[/tex] & 16 & 25 & 34 & 43 & \\
\hline
\end{tabular}

Fill in the missing value for [tex]$y$[/tex] when [tex]$x = 5$[/tex].



Answer :

Sure! Let's break down the process to find the missing \( y \) value when \( x = 5 \).

### Step-by-Step Solution:

1. List the Given Values:
We have the following pairs \((x, y)\):
- \( x = 1, y = 16 \)
- \( x = 2, y = 25 \)
- \( x = 3, y = 34 \)
- \( x = 4, y = 43 \)
- \( x = 5, y = ? \)

2. Calculate the Differences in \( x \) and \( y \):
- The differences in \( x \), also known as \( \Delta x \), are consistent due to equal spacing: \( \Delta x = 2 - 1 = 3 - 2 = 4 - 3 = 5 - 4 = 1 \).
- The differences in \( y \), also known as \( \Delta y \), can be calculated:
[tex]\[ \Delta y_1 = 25 - 16 = 9 \][/tex]
[tex]\[ \Delta y_2 = 34 - 25 = 9 \][/tex]
[tex]\[ \Delta y_3 = 43 - 34 = 9 \][/tex]

3. Determine the Average Rate of Change (Slope \( m \)):
- Since all \( \Delta y \) values are the same, the slope \( m \) between sequential \( y \) values is the same:
[tex]\[ m = \frac{\Delta y}{\Delta x} = \frac{9}{1} = 9 \][/tex]

4. Find the Equation of the Line:
- We know the slope \( m = 9 \) and a point on the line \( (x, y) = (4, 43) \).
- Using the point-slope form of the linear equation \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept:
[tex]\[ y = mx + b \][/tex]
- Plugging in the values \( y = 43 \), \( x = 4 \), and \( m = 9 \):
[tex]\[ 43 = 9 \cdot 4 + b \][/tex]
[tex]\[ 43 = 36 + b \][/tex]
[tex]\[ b = 43 - 36 = 7 \][/tex]

5. Using the Equation to Find the Missing \( y \):
- Now we have the equation of the line \( y = 9x + 7 \).
- To find \( y \) when \( x = 5 \):
[tex]\[ y = 9 \cdot 5 + 7 \][/tex]
[tex]\[ y = 45 + 7 \][/tex]
[tex]\[ y = 52 \][/tex]

Thus, the missing [tex]\( y \)[/tex] value for [tex]\( x = 5 \)[/tex] is [tex]\( \boxed{52} \)[/tex]. The slopes between sequential [tex]\( y \)[/tex] values were consistently [tex]\( 9.0 \)[/tex].

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