2. Solve the inequality: [tex]8x + 7 \ \textless \ 45x + 18[/tex]

A. [tex]x \ \textless \ -\frac{11}{37}[/tex]

B. [tex]x \ \textgreater \ -\frac{11}{37}[/tex]

C. [tex]x \ \textless \ \frac{11}{37}[/tex]

D. [tex]x \ \textgreater \ \frac{11}{37}[/tex]



Answer :

To solve the inequality \(8x + 7 < 45x + 18\), we need to isolate \(x\) on one side of the inequality. Let's proceed with the steps:

1. Subtract \(8x\) from both sides of the inequality:
[tex]\[ 8x + 7 - 8x < 45x + 18 - 8x \][/tex]
This simplifies to:
[tex]\[ 7 < 37x + 18 \][/tex]

2. Subtract 18 from both sides to further isolate the term involving \(x\):
[tex]\[ 7 - 18 < 37x + 18 - 18 \][/tex]
This simplifies to:
[tex]\[ -11 < 37x \][/tex]

3. To solve for \(x\), divide both sides by 37:
[tex]\[ \frac{-11}{37} < x \][/tex]

This can be rewritten as:
[tex]\[ x > -\frac{11}{37} \][/tex]

Therefore, the solution to the inequality \(8x + 7 < 45x + 18\) is:
[tex]\[ x > -\frac{11}{37} \][/tex]

So, the correct answer is:

B. [tex]\(x > -\frac{11}{37}\)[/tex]

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