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A triangle has vertices at [tex]$A(-2,-2)[tex]$[/tex], [tex]$[/tex]B(-1,1)[tex]$[/tex], and [tex]$[/tex]C(3,2)[tex]$[/tex]. Which of the following transformations produces an image with vertices [tex]$[/tex]A^{\prime}(-2,2)[tex]$[/tex], [tex]$[/tex]B^{\prime}(-1,-1)[tex]$[/tex], and [tex]$[/tex]C^{\prime}(3,-2)$[/tex]?

A. [tex]$(x, y) \rightarrow (x, -y)$[/tex]
B. [tex]$(x, y) \rightarrow (-y, x)$[/tex]
C. [tex]$(x, y) \rightarrow (-x, y)$[/tex]
D. [tex]$(x, y) \rightarrow (y, -x)$[/tex]



Answer :

To determine which transformation produces the specified image, we need to systematically apply each proposed transformation to the original vertices and see if we get the desired transformed vertices.

Step 1: Applying the first transformation [tex]$(x, y) \rightarrow (x, -y)$[/tex]

- For vertex \( A(-2, -2) \):
[tex]\[ (-2, -2) \rightarrow (-2, -(-2)) = (-2, 2) \][/tex]
- For vertex \( B(-1, 1) \):
[tex]\[ (-1, 1) \rightarrow (-1, -(1)) = (-1, -1) \][/tex]
- For vertex \( C(3, 2) \):
[tex]\[ (3, 2) \rightarrow (3, -(2)) = (3, -2) \][/tex]

Transformation [tex]$(x, y) \rightarrow (x, -y)$[/tex] results in the vertices: \(A^{\prime}(-2, 2)\), \(B^{\prime}(-1, -1)\), \(C^{\prime}(3, -2)\), which matches the given image vertices.

Conclusion:
The transformation \( (x, y) \rightarrow (x, -y) \) is the required transformation.

Therefore, the correct transformation that produces the given image is:
[tex]\[ \boxed{(x, y) \rightarrow (x, -y)} \][/tex]

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