A bottlenose dolphin is 10 feet below sea level. Then it begins to dive at a rate of 9 feet per second. What is the equation of the line that represents its elevation, [tex]y[/tex], after [tex]x[/tex] seconds?

A. [tex]y = 9x - 10[/tex]
B. [tex]y = -9x - 10[/tex]
C. [tex]y = 9x + 10[/tex]
D. [tex]y = -9x + 10[/tex]



Answer :

To determine the equation of the line representing the elevation of the dolphin after \( x \) seconds, we need to consider both the initial condition and the rate of change.

Let's break down the information provided:

1. Initial Elevation:
- The dolphin starts 10 feet below sea level. This means that at \( x = 0 \) seconds, the elevation \( y \) is -10 feet.

2. Rate of Change:
- The dolphin dives at a rate of 9 feet per second. This rate is a constant change in elevation and since it is diving, the elevation decreases with time. Therefore, this rate is negative: -9 feet per second.

Using the slope-intercept form of a linear equation \( y = mx + b \), where \( m \) is the slope (rate of change) and \( b \) is the y-intercept (initial elevation), we can plug in the given values:

- \( m = -9 \)
- \( b = -10 \)

Thus, the equation becomes:

[tex]\[ y = -9x - 10 \][/tex]

According to the options given:

A. \( y = 9x - 10 \)
B. \( y = -9x - 10 \)
C. \( y = 9x + 10 \)
D. \( y = -9x + 10 \)

The correct equation that represents the dolphin's elevation after \( x \) seconds is:

[tex]\[ \boxed{y = -9x - 10} \][/tex]

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