Answer :
Certainly! Let's solve the quadratic equation \(-3n^2 + 147 = 0\) step by step.
1. Start with the given equation:
[tex]\[ -3n^2 + 147 = 0 \][/tex]
2. Move 147 to the other side of the equation to isolate the quadratic term:
[tex]\[ -3n^2 = -147 \][/tex]
3. Divide both sides of the equation by -3 to solve for \(n^2\):
[tex]\[ n^2 = \frac{-147}{-3} \][/tex]
[tex]\[ n^2 = 49 \][/tex]
4. Take the square root of both sides to solve for \(n\):
[tex]\[ n = \pm \sqrt{49} \][/tex]
5. Calculate the square root of 49:
[tex]\[ n = \pm 7 \][/tex]
Therefore, the solutions are:
[tex]\[ n = \pm 7 \][/tex]
In the box, you should write:
[tex]\[ 7 \][/tex]
1. Start with the given equation:
[tex]\[ -3n^2 + 147 = 0 \][/tex]
2. Move 147 to the other side of the equation to isolate the quadratic term:
[tex]\[ -3n^2 = -147 \][/tex]
3. Divide both sides of the equation by -3 to solve for \(n^2\):
[tex]\[ n^2 = \frac{-147}{-3} \][/tex]
[tex]\[ n^2 = 49 \][/tex]
4. Take the square root of both sides to solve for \(n\):
[tex]\[ n = \pm \sqrt{49} \][/tex]
5. Calculate the square root of 49:
[tex]\[ n = \pm 7 \][/tex]
Therefore, the solutions are:
[tex]\[ n = \pm 7 \][/tex]
In the box, you should write:
[tex]\[ 7 \][/tex]