Your friend evaluated \( 3 + \frac{x^2}{y} \) when \( x = -2 \) and \( y = 4 \).

[tex]\[
\begin{aligned}
3 + \frac{x^2}{y} & = 3 + \frac{(-2)^2}{4} \\
& = 3 + \frac{4}{4} \\
& = 3 + 1 \\
& = 4
\end{aligned}
\][/tex]

What should your friend do to correct his error?

A. Divide 3 by 4 before subtracting.
B. Square -2, then divide.
C. Divide -2 by 4, then square.
D. Subtract 4 from 3 before dividing.

Answer: B. Square -2, then divide.



Answer :

To help your friend correct the error, let's carefully go through the expression \(3 + \frac{x^2}{y}\) step by step, ensuring we follow the correct order of operations:

1. Square -2:
[tex]\[ (-2)^2 = 4 \][/tex]
2. Divide the squared result by 4:
[tex]\[ \frac{4}{4} = 1.0 \][/tex]
3. Add this result to 3:
[tex]\[ 3 + 1.0 = 4.0 \][/tex]

Now, revisit the steps your friend took:

1. Your friend writes:
[tex]\[ 3 + (-2)^2 \div 4 \][/tex]
2. Here, your friend correctly squares -2:
[tex]\[ 3 + 4 \div 4 \][/tex]
3. But then incorrectly subtracts 4 instead of dividing:
[tex]\[ 3 - 4 \div 4 = 3 - 1 = 2 \][/tex]

To avoid this mistake, the division should be done before any addition/subtraction after the squaring step. The correct order should be to square \(-2\) first, then divide the result by 4, and finally add 3.

Thus, the correct approach is:

B. Square -2, then divide.

This matches our correct calculations and steps. The correct result is 4.0, and the correct option is B.

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