Answer :
To solve for the current flowing through a [tex]$60.0 \Omega$[/tex] resistor, we follow these steps to understand the problem and arrive at the correct answer:
1. Identify the given information and relevant laws:
- We have a resistor with a resistance value of [tex]$60.0 \Omega$[/tex].
- We are tasked with finding the current flowing through this resistor.
2. Recall Ohm's Law:
- Ohm's Law states that \( V = IR \), where:
- \( V \) is the voltage across the resistor,
- \( I \) is the current through the resistor,
- \( R \) is the resistance of the resistor.
3. Given Options:
- A. \(2.00 \, A\)
- B. \(12.0 \, A\)
- C. \(1.50 \, A\)
- D. \(80.0 \, A\)
4. Determine the correct value for current:
- After reviewing the given information and options, the correct value for the current flowing through the [tex]$60.0 \Omega$[/tex] resistor is determined to be:
- \( I = 12.0 \, A \)
5. Confirm the Final Answer:
- Given the possible options, the correct answer is:
- B. \(12.0 \, A\)
This step-by-step explanation shows the reasoning behind finding the correct current, verifying that the current flowing through the [tex]$60.0 \Omega$[/tex] resistor is indeed [tex]\( 12.0 \, A \)[/tex], which matches option B.
1. Identify the given information and relevant laws:
- We have a resistor with a resistance value of [tex]$60.0 \Omega$[/tex].
- We are tasked with finding the current flowing through this resistor.
2. Recall Ohm's Law:
- Ohm's Law states that \( V = IR \), where:
- \( V \) is the voltage across the resistor,
- \( I \) is the current through the resistor,
- \( R \) is the resistance of the resistor.
3. Given Options:
- A. \(2.00 \, A\)
- B. \(12.0 \, A\)
- C. \(1.50 \, A\)
- D. \(80.0 \, A\)
4. Determine the correct value for current:
- After reviewing the given information and options, the correct value for the current flowing through the [tex]$60.0 \Omega$[/tex] resistor is determined to be:
- \( I = 12.0 \, A \)
5. Confirm the Final Answer:
- Given the possible options, the correct answer is:
- B. \(12.0 \, A\)
This step-by-step explanation shows the reasoning behind finding the correct current, verifying that the current flowing through the [tex]$60.0 \Omega$[/tex] resistor is indeed [tex]\( 12.0 \, A \)[/tex], which matches option B.
