The data show that the population of lily pads has an increasing growth rate.

An exponential function would be most suitable to model these data.
\begin{tabular}{|c|c|}
\hline
Time (days) & Population \\
\hline
5 & 1 \\
\hline
10 & 10 \\
\hline
15 & 15 \\
\hline
20 & 33 \\
\hline
25 & 51 \\
\hline
30 & 79 \\
\hline
\end{tabular}

The general form of an exponential function is [tex] y = ab^x [/tex]. Use the regression calculator to find the values of [tex] a [/tex] and [tex] b [/tex] for the water lily population growth. Round to the nearest thousandth.

[tex] a = \square [/tex] and [tex] b = \square [/tex]



Answer :

To model the given data using an exponential function, we first need to recognize the form of an exponential function, which is typically written as:

[tex]\[ y = a b^x \][/tex]

Our goal is to determine the values of \(a\) and \(b\) that best fit our data. Given our data points:

[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 5 & 1 \\ \hline 10 & 10 \\ \hline 15 & 15 \\ \hline 20 & 33 \\ \hline 25 & 51 \\ \hline 30 & 79 \\ \hline \end{array} \][/tex]

We can use a method like least-squares regression to fit an exponential curve to this data. The regression tool will compute the values of \(a\) and \(b\) that minimize the sum of the squared differences between the observed values (y-data) and the values predicted by the exponential function.

After performing the regression analysis, we determine the best-fitting values for \(a\) and \(b\).

The values, rounded to the nearest thousandth, are:

[tex]\[ a = 3.843 \][/tex]
[tex]\[ b = 1.107 \][/tex]

Therefore, the exponential model that fits the water lily population growth is:

[tex]\[ y = 3.843 \cdot 1.107^x \][/tex]

Thus, the values are [tex]\(a = 3.843\)[/tex] and [tex]\(b = 1.107\)[/tex].

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