Given the building layout for Store A, Store B, Store C, and Store D, what portion of the shared $6000 security costs should be apportioned to Store A?

\begin{tabular}{|c|c|c|c|}
\hline
A & \begin{tabular}{c}
B \\
[tex]$625 \, \text{ft}^2$[/tex]
\end{tabular} & \begin{tabular}{c}
C \\
[tex]$625 \, \text{ft}^2$[/tex]
\end{tabular} & \multirow{2}{*}{[tex]$2500 \, \text{ft}^2$[/tex]} \\
\hline
[tex]$2500 \, \text{ft}^2$[/tex] & - & - & \\
\hline
\end{tabular}

Apportioned Cost [tex]$=\$[/tex][?]$



Answer :

Sure, let's break down the solution step-by-step for determining the portion of the shared $6000 security cost that should be apportioned to Store A.


### Step 1: Calculate the Total Area of All Stores

The area for each store is given as:

- Store A: \(2500 \, \text{ft}^2\)
- Store B: \(625 \, \text{ft}^2\)
- Store C: \(625 \, \text{ft}^2\)
- Store D: \(2500 \, \text{ft}^2\)

To find the total area, we sum up the individual areas of all the stores:
[tex]\[ \text{Total Area} = 2500 + 625 + 625 + 2500 = 6250 \, \text{ft}^2 \][/tex]

### Step 2: Calculate the Proportion of Store A's Area to the Total Area

Next, we need to find the proportion of the area that Store A occupies relative to the total area. This is done by dividing Store A's area by the total area:
[tex]\[ \text{Proportion of Store A} = \frac{\text{Store A Area}}{\text{Total Area}} = \frac{2500}{6250} = 0.4 \][/tex]

### Step 3: Calculate the Apportioned Cost for Store A

Now, we use the proportion calculated in Step 2 to find out how much of the $6000 security cost should be apportioned to Store A. We do this by multiplying the total security cost by the proportion of Store A:
[tex]\[ \text{Cost apportioned to Store A} = \text{Total Security Cost} \times \text{Proportion of Store A} = 6000 \times 0.4 = 2400 \][/tex]

Therefore, the portion of the shared $6000 security costs that should be apportioned to Store A is:
[tex]\[ \$2400 \][/tex]

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