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Drag the tiles to the boxes to form correct pairs.
Match the pairs of equivalent expressions.

A. \(\left(-14+\frac{3}{2} b\right)-\left(1+\frac{8}{2} b\right)\)

B. \(4b + \frac{13}{2}\)

C. \((5+2b) + \left(2b+\frac{3}{2}\right)\)

D. \(8b - 15\)

E. \(\left(\frac{7}{2}b - 3\right) - (8 + 6b)\)

F. \(\frac{-5}{2}b - 11\)

G. \((-10 + b) + (7b - 5)\)

H. [tex]\(-15 - \frac{5}{2}b\)[/tex]



Answer :

GinnyAnswer
Okay, let's match the pairs of equivalent expressions step-by-step:

1. Expression: \((-14 + \frac{3}{2} b) - (1 + \frac{8}{2} b)\)
- Simplify the expression:
[tex]\[ (-14 + \frac{3}{2} b) - (1 + \frac{8}{2} b) \][/tex]
[tex]\[ = -14 + \frac{3}{2} b - 1 - 4 b \][/tex]
[tex]\[ = -15 + \left(\frac{3}{2} - 4\right)b \][/tex]
[tex]\[ = -15 - \frac{5}{2} b \][/tex]
- Hence, the pair is: \((-14 + \frac{3}{2} b) - (1 + \frac{8}{2} b)\) and \(-15 - \frac{5}{2} b\).

2. Expression: \((5 + 2 b) + (2 b + \frac{3}{2})\)
- Simplify the expression:
[tex]\[ (5 + 2 b) + (2 b + \frac{3}{2}) \][/tex]
[tex]\[ = 5 + 2b + 2b + \frac{3}{2} \][/tex]
[tex]\[ = 5 + \frac{3}{2} + 4b \][/tex]
[tex]\[ = \frac{10}{2} + \frac{3}{2} + 4b \][/tex]
[tex]\[ = \frac{13}{2} + 4b \][/tex]
- Hence, the pair is: \((5 + 2 b) + (2 b + \frac{3}{2})\) and \(4 b + \frac{13}{2}\).

3. Expression: \(\left(\frac{7}{2} b - 3\right) - (8 + 6 b)\)
- Simplify the expression:
[tex]\[ \left(\frac{7}{2} b - 3\right) - (8 + 6 b) \][/tex]
[tex]\[ = \frac{7}{2} b - 3 - 8 - 6 b \][/tex]
[tex]\[ = -3 - 8 + \left(\frac{7}{2} - 6\right) b \][/tex]
[tex]\[ = -11 - \frac{5}{2} b \][/tex]
- Hence, the pair is: \((\frac{7}{2} b - 3) - (8 + 6 b)\) and \(-11 - \frac{5}{2} b\).

4. Expression: \((-10 + b) + (7 b - 5)\)
- Simplify the expression:
[tex]\[ (-10 + b) + (7 b - 5) \][/tex]
[tex]\[ = -10 + b + 7b - 5 \][/tex]
[tex]\[ = -10 - 5 + 8b \][/tex]
[tex]\[ = -15 + 8b \][/tex]
- Hence, the pair is: \((-10 + b) + (7 b - 5)\) and \(8 b - 15\).

Therefore, the correct pairs are:
1. \((-14 + \frac{3}{2} b) - (1 + \frac{8}{2} b)\) and \(-15 - \frac{5}{2} b\).
2. \((5 + 2 b) + (2 b + \frac{3}{2})\) and \(4 b + \frac{13}{2}\).
3. \((\frac{7}{2} b - 3) - (8 + 6 b)\) and \(-11 - \frac{5}{2} b\).
4. [tex]\((-10 + b) + (7 b - 5)\)[/tex] and [tex]\(8 b - 15\)[/tex].

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