Answer :
Answer:
4/3
-1
Step-by-step explanation:
Consider that number as x, the condition is represented by the equation
[tex]3x^2-x = 4[/tex]
where x is the number, subtracted by 3x^2, which gives 4.
With this, all you need to do is solve for x by quadratic.
[tex]3x^2-x = 4\\3x^2-x-4 = 0\\x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
[tex]a = 3 \\b= -1\\x = -4[/tex]
[tex]x = \frac{-(-1)\pm\sqrt{(-1)^2-4(3)(-4)}}{2(3)}[/tex]
[tex]x = \frac{1\pm\sqrt{1+48}}{6}[/tex]
[tex]x = \frac{1\pm\sqrt{49}}{6}[/tex]
[tex]x = \frac{1\pm7}{6}[/tex]
[tex]x_1 = \frac{8}{6} = 4/3\\x_2 = \frac{-6}{6} = -1[/tex]
