Answer :
Certainly! Let's solve the equation \(13W = 4a - 3b\) step-by-step to find the value of \(W\) when \(a = 5\) and \(b = 2\).
1. Substitute the values of \(a\) and \(b\) into the equation:
\(a = 5\) and \(b = 2\).
2. Plug these values into the given equation:
[tex]\[ 13W = 4(5) - 3(2) \][/tex]
3. Compute the products:
[tex]\[ 4 \cdot 5 = 20 \][/tex]
[tex]\[ 3 \cdot 2 = 6 \][/tex]
4. Substitute these computed values back into the equation:
[tex]\[ 13W = 20 - 6 \][/tex]
5. Perform the subtraction:
[tex]\[ 13W = 14 \][/tex]
6. Solve for \(W\) by dividing both sides of the equation by 13:
[tex]\[ W = \frac{14}{13} \][/tex]
7. Simplify the fraction to get the final value of \(W\):
[tex]\[ W = \frac{14}{13} \approx 1.0769230769230769 \][/tex]
So, when [tex]\(a = 5\)[/tex] and [tex]\(b = 2\)[/tex], the value of [tex]\(W\)[/tex] is approximately [tex]\(1.0769230769230769\)[/tex].
1. Substitute the values of \(a\) and \(b\) into the equation:
\(a = 5\) and \(b = 2\).
2. Plug these values into the given equation:
[tex]\[ 13W = 4(5) - 3(2) \][/tex]
3. Compute the products:
[tex]\[ 4 \cdot 5 = 20 \][/tex]
[tex]\[ 3 \cdot 2 = 6 \][/tex]
4. Substitute these computed values back into the equation:
[tex]\[ 13W = 20 - 6 \][/tex]
5. Perform the subtraction:
[tex]\[ 13W = 14 \][/tex]
6. Solve for \(W\) by dividing both sides of the equation by 13:
[tex]\[ W = \frac{14}{13} \][/tex]
7. Simplify the fraction to get the final value of \(W\):
[tex]\[ W = \frac{14}{13} \approx 1.0769230769230769 \][/tex]
So, when [tex]\(a = 5\)[/tex] and [tex]\(b = 2\)[/tex], the value of [tex]\(W\)[/tex] is approximately [tex]\(1.0769230769230769\)[/tex].
