Describe the position of the source and the range of the signals.

The equation [tex]$(x+6)^2 + (y+4)^2 = 36$[/tex] models the position and range of the source of a radio signal.



Answer :

To describe the position of the source and the range of the signals modeled by the equation \((x+6)^2 + (y+4)^2 = 36\), we will interpret this equation in the context of the standard form of a circle equation \((x - h)^2 + (y - k)^2 = r^2\).

### Identifying the Center
The standard form of the equation of a circle is:
[tex]\[ (x - h)^2 + (y - k)^2 = r^2 \][/tex]
where \((h, k)\) is the center of the circle and \(r\) is the radius.

By comparing the given equation \((x+6)^2 + (y+4)^2 = 36\) with the standard form:

- We can see that the terms \((x + 6)\) and \((y + 4)\) correspond to \((x - (-6))\) and \((y - (-4))\) respectively, indicating that the center \((h, k)\) of the circle is at \((-6, -4)\).

### Identifying the Radius
The constant on the right-hand side of the equation, 36, corresponds to \(r^2\) in the standard form. To find the radius \(r\), we take the square root of 36:

[tex]\[ r = \sqrt{36} = 6 \][/tex]

### Conclusion
1. The position of the source of the radio signal, which corresponds to the center of the circle, is at \((-6, -4)\).
2. The range of the signal, which corresponds to the radius of the circle, is 6 units.

Hence, the position of the source of the radio signal is [tex]\((-6, -4)\)[/tex], and the range of the signals is 6 units.

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