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A baseball is struck by a bat. If the bat is in contact with the ball for 0.01 s and the average force applied by the bat is 965.5 N, calculate the impulse delivered to the ball by the bat.

Give your answer to 2 decimal places.

Your Answer: __________ units



Answer :

GinnyAnswer
To calculate the impulse delivered to the ball by the bat, we use the formula for impulse:

[tex]\[ \text{Impulse} = \text{Average Force} \times \text{Time} \][/tex]

Given the values:
- The time of contact (\( t \)) is \( 0.01 \) seconds.
- The average force (\( F \)) exerted by the bat is \( 965.5 \) Newtons.

Plug these values into the formula:

[tex]\[ \text{Impulse} = 965.5 \, \text{N} \times 0.01 \, \text{s} \][/tex]

Multiplying these values:

[tex]\[ \text{Impulse} = 9.655 \, \text{Ns} \][/tex]

When rounded to two decimal places, we get:

[tex]\[ \text{Impulse} = 9.65 \, \text{Ns} \][/tex]

Therefore, the impulse delivered to the ball by the bat is [tex]\( 9.65 \, \text{Ns} \)[/tex].
Impulse (\( J \)) is calculated by the formula:

\[ J = F \cdot \Delta t \]

where:
- \( F \) is the average force applied (965.5 N)
- \( \Delta t \) is the time duration the force is applied (0.01 s)

Plugging in the values:

\[ J = 965.5 \, \text{N} \times 0.01 \, \text{s} \]
\[ J = 9.655 \, \text{N} \cdot \text{s} \]

Rounded to two decimal places, the impulse is:

\[ J = 9.66 \, \text{N} \cdot \text{s} \]

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