Consider the chemical reaction below.
[tex]\[ Zn (s) + 2 H^+(aq) \longrightarrow Zn^{2+}(aq) + H_2(g) \][/tex]

Which half-reaction correctly represents reduction for this equation?

A. \( Zn (s) \longrightarrow Zn^{2+}(aq) + 2e^- \)

B. \( 2 H^+(aq) + 2e^- \longrightarrow H_2(g) \)

C. \( Zn (s) \longrightarrow Zn^{2+}(aq) + e^- \)

D. [tex]\( 2 H^+(aq) + e^- \longrightarrow H_2(g) \)[/tex]



Answer :

Let's analyze the given chemical reaction and the associated half-reactions to determine which one correctly represents the reduction process.

The full reaction is:
[tex]\[ Zn (s) + 2 H^+ (aq) \longrightarrow Zn^{2+} (aq) + H_2 (g) \][/tex]

In any redox reaction, there are two processes occurring: oxidation and reduction.

Oxidation involves the loss of electrons:
[tex]\[ \text{Zn (s)} \rightarrow \text{Zn}^{2+} \text{(aq)} + 2 e^- \][/tex]

Reduction involves the gain of electrons. Here, we need to determine which species gains electrons. The evolution of hydrogen gas (\( H_2 \)) suggests that \( H^+ \) ions gain electrons to form \( H_2 \) gas.

So we look for the half-reaction where \( H^+ \) gains electrons. The options provided are:

1. \( Zn (s) \longrightarrow Zn^{2+} (aq) + 2 e^- \)
2. \( 2 H^+ (aq) + 2 e^- \longrightarrow H_2 (g) \)
3. \( Zn (s) \longrightarrow Zn^{2+} (aq) + e^- \)
4. \( 2 H^+ (aq) + e^- \longrightarrow H_2 (g) \)

Among these, option 2 correctly represents the reduction half-reaction:
[tex]\[ 2 H^+ (aq) + 2 e^- \longrightarrow H_2 (g) \][/tex]

This half-reaction shows that hydrogen ions (\( H^+ \)) gain electrons to form hydrogen gas (\( H_2 \)).

Thus, the correct half-reaction representing reduction in the given chemical equation is:
[tex]\[ 2 H^+ (aq) + 2 e^- \longrightarrow H_2 (g) \][/tex]

And correspondingly, the correct option is:
[tex]\[ 2 \][/tex]

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