Answer :
Certainly! To solve this problem, we need to use the given formula:
[tex]\[ F = ma \][/tex]
Where:
- \( F \) is the force applied, which is 12 N (Newtons).
- \( m \) is the mass of the wagon, which we need to find.
- \( a \) is the acceleration, which is 3 \( \text{m/s}^2 \) (meters per second squared).
We are asked to find the mass \( m \). To do this, we need to rearrange the formula to solve for \( m \):
[tex]\[ m = \frac{F}{a} \][/tex]
Now, we can substitute in the given values:
[tex]\[ m = \frac{12 \, \text{N}}{3 \, \text{m/s}^2} \][/tex]
When we divide 12 by 3, we get:
[tex]\[ m = 4 \, \text{kg} \][/tex]
Therefore, the mass of the wagon is:
[tex]\[ \boxed{4 \, \text{kg}} \][/tex]
So, the correct answer is 4 kg.
[tex]\[ F = ma \][/tex]
Where:
- \( F \) is the force applied, which is 12 N (Newtons).
- \( m \) is the mass of the wagon, which we need to find.
- \( a \) is the acceleration, which is 3 \( \text{m/s}^2 \) (meters per second squared).
We are asked to find the mass \( m \). To do this, we need to rearrange the formula to solve for \( m \):
[tex]\[ m = \frac{F}{a} \][/tex]
Now, we can substitute in the given values:
[tex]\[ m = \frac{12 \, \text{N}}{3 \, \text{m/s}^2} \][/tex]
When we divide 12 by 3, we get:
[tex]\[ m = 4 \, \text{kg} \][/tex]
Therefore, the mass of the wagon is:
[tex]\[ \boxed{4 \, \text{kg}} \][/tex]
So, the correct answer is 4 kg.
