Matt conducted an experiment to study the solubility of two substances. He poured [tex]$100 \, \text{mL}[tex]$[/tex] of water at [tex]200^{\circ} \text{C}$[/tex][/tex] into each of two beakers labeled A and B. He put [tex]$50 \, \text{g}$[/tex] of Substance A in Beaker A and Substance B in Beaker B. The experiment was repeated for different temperatures of water, and the observations were recorded as shown.

Experimental Observations
\begin{tabular}{|c|c|c|c|c|}
\hline \multirow{2}{*}{ Substance } & \multicolumn{4}{|c|}{ Mass of Undissolved Substance at Different Temperatures (grams) } \\
\hline & [tex]$20^{\circ} C$[/tex] & [tex]$40^{\circ} C$[/tex] & [tex]$60^{\circ} C$[/tex] & [tex]$80^{\circ} C$[/tex] \\
\hline A & 50 & 50 & 50 & 50 \\
\hline B & 10 & 8 & 5 & 2 \\
\hline
\end{tabular}

Part 1: Which, if any, substance is soluble in water?

Part 2: Explain how the data helped you determine solubility for both substances for temperatures [tex]$20^{\circ} C[tex]$[/tex] to [tex]$[/tex]80^{\circ} C$[/tex].



Answer :

Sure, let's break down the given observations and determine the solubility of both substances from the data recorded in the table.

### Part 1: Which, if any, substance is soluble in water?
Based on the observations, we have the following data for the mass of undissolved substances at different temperatures:
- Substance A: 50 g (remaining the same at all temperatures: 20°C, 40°C, 60°C, and 80°C)
- Substance B: 10 g at 20°C, 8 g at 40°C, 5 g at 60°C, and 2 g at 80°C

From analyzing this data, we can conclude the following:
- Substance A is not soluble in water.
- Substance B is soluble in water.

### Part 2: Explanation of Solubility Determination

#### Substance A:
- For Substance A, the mass of undissolved substance remains constant at 50 g across all temperatures (20°C, 40°C, 60°C, and 80°C).
- Because the undissolved mass of Substance A does not change with increasing temperature, we can infer that none of the Substance A is dissolving in water irrespective of the temperature.
- In other words, Substance A does not dissolve in water at these temperatures, indicating that it is insoluble.

#### Substance B:
- For Substance B, the mass of undissolved substance decreases as the temperature increases: 10 g at 20°C, 8 g at 40°C, 5 g at 60°C, and 2 g at 80°C.
- This trend shows that as the temperature of the water increases, more of Substance B dissolves, leading to a decreasing amount of undissolved mass.
- The decrease in the undissolved mass of Substance B with increasing temperature is a clear indication that Substance B is soluble in water. It dissolves more effectively at higher temperatures.

### Conclusion:
- Substance A is not soluble in water at temperatures from 20°C to 80°C because the undissolved mass remains unchanged.
- Substance B is soluble in water at these temperatures, with its solubility increasing as the temperature rises, as evidenced by the decreasing undissolved mass.

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