Fairview High School has an anime (Japanese animation) club that any student can attend. The relative frequency table shows the proportion of students in the high school who take Japanese and/or are in the anime club.

\begin{tabular}{|c|c|c|c|}
\hline & \begin{tabular}{c}
Take \\
Japanese
\end{tabular} & \begin{tabular}{c}
Do not take \\
Japanese
\end{tabular} & Total \\
\hline In anime club & 0.13 & 0.01 & 0.14 \\
\hline \begin{tabular}{c}
Not in anime \\
club
\end{tabular} & 0.05 & 0.81 & 0.86 \\
\hline Total & 0.18 & 0.82 & 1.0 \\
\hline
\end{tabular}

Given that a student is in the anime club, what is the likelihood that he or she takes Japanese?

A. About [tex]$93 \%$[/tex]

B. [tex]$13 \%$[/tex]

C. About [tex]$72 \%$[/tex]

D. [tex]$18 \%$[/tex]

To determine the likelihood that a student takes Japanese given that they are in the anime club, we need to calculate the conditional probability. Specifically, we seek $ P(\text{Take Japanese} \mid \text{In Anime Club}) $.

Based on the given table:

- The proportion of students who take Japanese and are in the anime club is $ P(\text{Take Japanese and In Anime Club}) = 0.13 $.
- The proportion of students who are in the anime club is $ P(\text{In Anime Club}) = 0.14 $.

The conditional probability $ P(\text{Take Japanese} \mid \text{In Anime Club}) $ is given by the following formula:

[tex]\[ P(\text{Take Japanese} \mid \text{In Anime Club}) = \frac{P(\text{Take Japanese and In Anime Club})}{P(\text{In Anime Club})} \][/tex]

Substituting the given values:

[tex]\[ P(\text{Take Japanese} \mid \text{In Anime Club}) = \frac{0.13}{0.14} \][/tex]

Performing the division:

[tex]\[ P(\text{Take Japanese} \mid \text{In Anime Club}) \approx 0.9285714285714285 \][/tex]

Converting this to a percentage:

[tex]\[ 0.9285714285714285 \times 100 \approx 92.85714285714285\% \][/tex]

Therefore, the likelihood that a student takes Japanese given that they are in the anime club is about 93%.

Thus, the correct answer is:
A. About [tex]$ 93\% $[/tex]