Answer :
Sure, let's go through each part of the problem step by step.
### 1. Arrange in ascending order:
Given fractions:
[tex]\[ \frac{4}{8}, \frac{3}{7}, \frac{5}{6}, \frac{4}{3} \][/tex]
First, we convert these fractions to their decimal form to compare them easily:
[tex]\[ \frac{4}{8} = 0.5, \qquad \frac{3}{7} \approx 0.428571, \qquad \frac{5}{6} \approx 0.833333, \qquad \frac{4}{3} \approx 1.333333 \][/tex]
Now we arrange these decimal values in ascending order:
[tex]\[ 0.428571, 0.5, 0.833333, 1.333333 \][/tex]
So, the fractions in ascending order are:
[tex]\[ \frac{3}{7}, \frac{4}{8}, \frac{5}{6}, \frac{4}{3} \][/tex]
### 2. Arrange in ascending order:
Given fractions:
[tex]\[ \frac{2}{7}, \frac{11}{35}, \frac{9}{14}, \frac{3}{28} \][/tex]
We convert these fractions to their decimal form:
[tex]\[ \frac{2}{7} \approx 0.285714, \qquad \frac{11}{35} \approx 0.314286, \qquad \frac{9}{14} \approx 0.642857, \qquad \frac{3}{28} \approx 0.107143 \][/tex]
Then we arrange these decimal values in ascending order:
[tex]\[ 0.107143, 0.285714, 0.314286, 0.642857 \][/tex]
So, the fractions in ascending order are:
[tex]\[ \frac{3}{28}, \frac{2}{7}, \frac{11}{35}, \frac{9}{14} \][/tex]
### 3. Who solved lesser part?
Ramesh solved \(\frac{2}{7}\) part of the exercise and Seema solved \(\frac{4}{5}\) of it. We need to compare these values.
First, we find their decimal equivalents:
[tex]\[ \frac{2}{7} \approx 0.285714 \][/tex]
[tex]\[ \frac{4}{5} = 0.8 \][/tex]
Comparing these values:
[tex]\[ 0.285714 < 0.8 \][/tex]
Therefore, Ramesh solved the lesser part of the exercise.
### 4. What is the total weight of fruits purchased by Sameera?
Sameera purchased \(\frac{7}{2}\) kg of apples and \(\frac{19}{3}\) kg of oranges.
Convert these fractions to decimal form:
[tex]\[ \frac{7}{2} = 3.5 \][/tex]
[tex]\[ \frac{19}{3} \approx 6.333333 \][/tex]
Now, add these weights to find the total weight:
[tex]\[ 3.5 + 6.333333 = 9.833333 \][/tex]
So, the total weight of fruits purchased by Sameera is approximately [tex]\(9.833333\)[/tex] kg.
### 1. Arrange in ascending order:
Given fractions:
[tex]\[ \frac{4}{8}, \frac{3}{7}, \frac{5}{6}, \frac{4}{3} \][/tex]
First, we convert these fractions to their decimal form to compare them easily:
[tex]\[ \frac{4}{8} = 0.5, \qquad \frac{3}{7} \approx 0.428571, \qquad \frac{5}{6} \approx 0.833333, \qquad \frac{4}{3} \approx 1.333333 \][/tex]
Now we arrange these decimal values in ascending order:
[tex]\[ 0.428571, 0.5, 0.833333, 1.333333 \][/tex]
So, the fractions in ascending order are:
[tex]\[ \frac{3}{7}, \frac{4}{8}, \frac{5}{6}, \frac{4}{3} \][/tex]
### 2. Arrange in ascending order:
Given fractions:
[tex]\[ \frac{2}{7}, \frac{11}{35}, \frac{9}{14}, \frac{3}{28} \][/tex]
We convert these fractions to their decimal form:
[tex]\[ \frac{2}{7} \approx 0.285714, \qquad \frac{11}{35} \approx 0.314286, \qquad \frac{9}{14} \approx 0.642857, \qquad \frac{3}{28} \approx 0.107143 \][/tex]
Then we arrange these decimal values in ascending order:
[tex]\[ 0.107143, 0.285714, 0.314286, 0.642857 \][/tex]
So, the fractions in ascending order are:
[tex]\[ \frac{3}{28}, \frac{2}{7}, \frac{11}{35}, \frac{9}{14} \][/tex]
### 3. Who solved lesser part?
Ramesh solved \(\frac{2}{7}\) part of the exercise and Seema solved \(\frac{4}{5}\) of it. We need to compare these values.
First, we find their decimal equivalents:
[tex]\[ \frac{2}{7} \approx 0.285714 \][/tex]
[tex]\[ \frac{4}{5} = 0.8 \][/tex]
Comparing these values:
[tex]\[ 0.285714 < 0.8 \][/tex]
Therefore, Ramesh solved the lesser part of the exercise.
### 4. What is the total weight of fruits purchased by Sameera?
Sameera purchased \(\frac{7}{2}\) kg of apples and \(\frac{19}{3}\) kg of oranges.
Convert these fractions to decimal form:
[tex]\[ \frac{7}{2} = 3.5 \][/tex]
[tex]\[ \frac{19}{3} \approx 6.333333 \][/tex]
Now, add these weights to find the total weight:
[tex]\[ 3.5 + 6.333333 = 9.833333 \][/tex]
So, the total weight of fruits purchased by Sameera is approximately [tex]\(9.833333\)[/tex] kg.
