Punnett square for taster vs. nontaster heritability:

\begin{tabular}{|l|c|c|}
\hline & \begin{tabular}{c}
MOM \\
[tex]$Tn$[/tex]
\end{tabular} & \begin{tabular}{c}
DAD \\
[tex]$nn$[/tex]
\end{tabular} \\
\hline CHILD 1 & [tex]$T$[/tex] & [tex]$n$[/tex] \\
\hline CHILD 2 & [tex]$n$[/tex] & [tex]$n$[/tex] \\
\hline CHILD 3 & [tex]$T$[/tex] & [tex]$n$[/tex] \\
\hline CHILD 4 & [tex]$n$[/tex] & [tex]$n$[/tex] \\
\hline
\end{tabular}

Key:
[tex]$T =$[/tex] "taster" (dominant trait) \\
[tex]$n =$[/tex] "nontaster" (recessive trait)

Recall that the trait of being a taster is a dominant trait. Which, if either, of the parents in the family can taste the bitter flavor of Brussels sprouts?

A. Mom \\
B. Dad \\
C. Both Mom and Dad \\
D. Neither Mom nor Dad



Answer :

To determine which parents in the family can taste the bitter flavor of Brussels sprouts, let's use the genetic information provided. The trait for being able to taste the bitter flavor of Brussels sprouts is dominant (T), while being a nontaster is recessive (n).

Given:
- Mom's genotype is Tn.
- Dad's genotype is nn.

### Analyzing Mom's Genotype (Tn)
- Mom has one dominant allele (T) and one recessive allele (n).
- Because the trait is dominant, having at least one T allele means Mom can taste the bitter flavor of Brussels sprouts.

### Analyzing Dad's Genotype (nn)
- Dad has two recessive alleles (n).
- Since Dad does not have any dominant allele (T), he cannot taste the bitter flavor of Brussels sprouts.

### Conclusion:
- Mom can taste the bitter flavor (because she has the Tn genotype).
- Dad cannot taste the bitter flavor (because he has the nn genotype).

So, the results are:
- Mom can taste the bitter flavor.
- Dad cannot taste the bitter flavor.

Thus, the correct answer is:
- Mom

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