Answer :
To solve the problem of how many milliliters of oxygen are in a 60 ml sample of seawater, given that the oxygen percentage is 85.84%, follow these steps:
1. Identify the given data:
- The total volume of the seawater sample: \( 60 \) ml
- The percentage of oxygen in the sample: \( 85.84 \% \)
2. Convert the percentage of oxygen to a decimal for calculation:
- \( 85.84\% = 0.8584 \)
3. Multiply the total volume of the sample by the decimal form of the oxygen percentage to find the oxygen volume in the sample:
- \( \text{Volume of oxygen} = \text{Total volume} \times \text{Oxygen percent as a decimal} \)
- \( \text{Volume of oxygen} = 60 \, \text{ml} \times 0.8584 \)
4. Calculate the resulting volume:
- \( \text{Volume of oxygen} = 60 \times 0.8584 = 51.504 \, \text{ml} \)
Thus, there are [tex]\( 51.504 \)[/tex] ml of oxygen in the 60 ml sample of seawater.
1. Identify the given data:
- The total volume of the seawater sample: \( 60 \) ml
- The percentage of oxygen in the sample: \( 85.84 \% \)
2. Convert the percentage of oxygen to a decimal for calculation:
- \( 85.84\% = 0.8584 \)
3. Multiply the total volume of the sample by the decimal form of the oxygen percentage to find the oxygen volume in the sample:
- \( \text{Volume of oxygen} = \text{Total volume} \times \text{Oxygen percent as a decimal} \)
- \( \text{Volume of oxygen} = 60 \, \text{ml} \times 0.8584 \)
4. Calculate the resulting volume:
- \( \text{Volume of oxygen} = 60 \times 0.8584 = 51.504 \, \text{ml} \)
Thus, there are [tex]\( 51.504 \)[/tex] ml of oxygen in the 60 ml sample of seawater.
