Answer :
To solve the problem of determining the approximate acceleration measured by an accelerometer, we can break down our thought process as follows:
1. Understanding the Relationship:
The accelerometer uses the extension of a spring to measure acceleration. Generally, this relationship is linear for small displacements, meaning the extension of the spring is proportional to the acceleration.
2. Given Data:
We are provided with an extension of the spring, which is 0.43 centimeters, and we need to determine the corresponding acceleration in terms of Earth's gravitational acceleration (g).
3. Comparing Extension to Given Choices:
Since the relationship between the extension and acceleration is linear, each option represents a specific ratio between the extension and the measured acceleration.
4. Selecting the Closest Approximation:
By evaluating the provided choices:
- 0.24 g
- 0.80 g
- 2.00 g
- 2.40 g
We estimate that for an extension of 0.43 centimeters, the likely acceleration falls closest to the value of 0.80 g.
Therefore, the approximate acceleration corresponding to a 0.43 centimeter extension of the accelerometer spring is [tex]\( \boxed{0.80 \, g} \)[/tex].
1. Understanding the Relationship:
The accelerometer uses the extension of a spring to measure acceleration. Generally, this relationship is linear for small displacements, meaning the extension of the spring is proportional to the acceleration.
2. Given Data:
We are provided with an extension of the spring, which is 0.43 centimeters, and we need to determine the corresponding acceleration in terms of Earth's gravitational acceleration (g).
3. Comparing Extension to Given Choices:
Since the relationship between the extension and acceleration is linear, each option represents a specific ratio between the extension and the measured acceleration.
4. Selecting the Closest Approximation:
By evaluating the provided choices:
- 0.24 g
- 0.80 g
- 2.00 g
- 2.40 g
We estimate that for an extension of 0.43 centimeters, the likely acceleration falls closest to the value of 0.80 g.
Therefore, the approximate acceleration corresponding to a 0.43 centimeter extension of the accelerometer spring is [tex]\( \boxed{0.80 \, g} \)[/tex].
