Answer :

To solve the equation \(\log_4 \sqrt{75x + 7} = 2\), let's follow a detailed step-by-step approach.

1. Understand the logarithm equation:

The equation given is:
[tex]\[ \log _4 \sqrt{75x + 7} = 2 \][/tex]
This means that the logarithm base 4 of \(\sqrt{75x + 7}\) equals 2.

2. Rewrite the logarithm equation:

We know that if \( \log_b(y) = z \), then \( b^z = y \). Using this property, we can rewrite the equation as:
[tex]\[ 4^2 = \sqrt{75x + 7} \][/tex]

3. Calculate the value of the exponent:

Simplify the right-hand side:
[tex]\[ 4^2 = 16 \][/tex]
So the equation now reads:
[tex]\[ 16 = \sqrt{75x + 7} \][/tex]

4. Remove the square root by squaring both sides:

Squaring both sides of the equation will eliminate the square root:
[tex]\[ 16^2 = (\sqrt{75x + 7})^2 \][/tex]
Simplifying this:
[tex]\[ 256 = 75x + 7 \][/tex]

5. Solve for \(x\):

To isolate \(x\), subtract 7 from both sides:
[tex]\[ 256 - 7 = 75x \][/tex]
Simplifying this yields:
[tex]\[ 249 = 75x \][/tex]

Now, divide both sides by 75 to solve for \(x\):
[tex]\[ x = \frac{249}{75} \][/tex]

6. Simplify the fraction:

Reduce the fraction \(\frac{249}{75}\) to its simplest form by finding the greatest common divisor of 249 and 75, which is 3:
[tex]\[ x = \frac{249 \div 3}{75 \div 3} = \frac{83}{25} \][/tex]

Therefore, the solution to the equation \(\log_4 \sqrt{75x + 7} = 2\) is:
[tex]\[ x = \frac{83}{25} \][/tex]

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