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Use the data in the table below to arrange the species in relative descending order from largest to smallest.

\begin{tabular}{|c|c|c|}
\hline Species & Type & Average Size \\
\hline Escherichia coli & Bacteria & [tex]$2.00 \mu m$[/tex] \\
\hline Rabies lyssavirus & Virus & [tex]$180.0 nm$[/tex] \\
\hline Naegleria fowleri & Protozoa & [tex]$12.0 \mu m$[/tex] \\
\hline Loa loa & Helminth & [tex]$24.0 mm$[/tex] \\
\hline Influenza B virus & Virus & [tex]$90.0 nm$[/tex] \\
\hline
\end{tabular}

Multiple Choice:
A. L. loa [tex]$\ \textgreater \ $[/tex] N. fowleri [tex]$\ \textgreater \ $[/tex] E. coli [tex]$\ \textgreater \ $[/tex] Rabies lyssavirus [tex]$\ \textgreater \ $[/tex] Influenza B virus

B. Rabies lyssavirus [tex]$\ \textgreater \ $[/tex] Influenza B virus [tex]$\ \textgreater \ $[/tex] L. loa [tex]$\ \textgreater \ $[/tex] N. fowleri [tex]$\ \textgreater \ $[/tex] E. coli

C. Rabies lyssavirus [tex]$\ \textgreater \ $[/tex] Influenza B virus [tex]$\ \textgreater \ $[/tex] N. fowleri [tex]$\ \textgreater \ $[/tex] E. coli [tex]$\ \textgreater \ $[/tex] L. loa

D. E. coli [tex]$\ \textgreater \ $[/tex] Rabies lyssavirus [tex]$\ \textgreater \ $[/tex] N. fowleri [tex]$\ \textgreater \ $[/tex] L. loa [tex]$\ \textgreater \ $[/tex] Influenza B virus



Answer :

GinnyAnswer
To arrange the species in descending order based on their average size, we need to convert all given sizes into a common unit and compare them. The sizes in micrometers (\(\mu m\)), nanometers (nm), and millimeters (mm) can all be converted to meters (m) for easier comparison.

Let's convert the sizes to meters:

1. Escherichia coli:
- Average Size = \(2.00 \mu m = 2.00 \times 10^{-6} \) meters

2. Rabies lyssavirus:
- Average Size = \(180.0 nm = 180.0 \times 10^{-9} \) meters

3. Naegleria fowleri:
- Average Size = \(12.0 \mu m = 12.0 \times 10^{-6} \) meters

4. Loa loa:
- Average Size = \(24.0 mm = 24.0 \times 10^{-3} \) meters

5. Influenza B virus:
- Average Size = \(90.0 nm = 90.0 \times 10^{-9} \) meters

Now, we compare these sizes:

- Loa loa: \(24.0 \times 10^{-3} \) meters
- Naegleria fowleri: \(12.0 \times 10^{-6} \) meters
- Escherichia coli: \(2.00 \times 10^{-6} \) meters
- Rabies lyssavirus: \(180.0 \times 10^{-9} \) meters
- Influenza B virus: \(90.0 \times 10^{-9} \) meters

In descending order of size, the list is:

- Loa loa
- Naegleria fowleri
- Escherichia coli
- Rabies lyssavirus
- Influenza B virus

Thus, the correct answer is:

L. loa [tex]\( > \)[/tex] N. fowleri [tex]\( > \)[/tex] E. coli [tex]\( > \)[/tex] Rabies lyssavirus [tex]\( > \)[/tex] Influenza B virus

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