Evaluate [tex]$3 x^2 - 2 x y - 4 y^2[tex]$[/tex] when [tex]$[/tex]x = 2[tex]$[/tex] and [tex]$[/tex]y = -3$[/tex].

A. [tex]-12[/tex]
B. [tex]36[/tex]
C. [tex]-36[/tex]
D. [tex]12[/tex]



Answer :

Sure, let's evaluate the expression \(3x^2 - 2xy - 4y^2\) step by step given \(x = 2\) and \(y = -3\).

1. Substitute the given values of \(x\) and \(y\) into the expression:
[tex]\[ 3(2)^2 - 2(2)(-3) - 4(-3)^2 \][/tex]

2. Calculate each term separately:
- First term: \(3(2)^2 = 3 \cdot 4 = 12\)
- Second term: \(-2(2)(-3) = -2 \cdot 2 \cdot -3 = 4 \cdot 3 = 12\)
- Third term: \(-4(-3)^2 = -4 \cdot 9 = -36\)

3. Combine all the terms:
[tex]\[ 12 + 12 - 36 \][/tex]

4. Simplify the result:
[tex]\[ 12 + 12 = 24 \][/tex]
[tex]\[ 24 - 36 = -12 \][/tex]

Therefore, the value of the expression [tex]\(3x^2 - 2xy - 4y^2\)[/tex] when [tex]\(x = 2\)[/tex] and [tex]\(y = -3\)[/tex] is [tex]\(-12\)[/tex]. So, the correct answer is [tex]\(\boxed{-12}\)[/tex].

Other Questions