Answer:
18V
Explanation:
When two resistors R1 and R2 are arranged in parallel then the effective/ total resistance
[tex] \frac{1}{ \: \:R_{ \:T}} = \frac{1}{ \ \: R_{1} } + \frac{1}{ \ \: R_{2} } [/tex]
[tex]\frac{1}{ \: \:R_{ \:T}} = \frac{1}{30} + \frac{1}{60} [/tex]
[tex]\frac{1}{ \: \:R_{ \:T}} = \frac{2 + 1}{60} [/tex]
[tex]\frac{1}{ \: \:R_{ \:T}} = \frac{3}{60} = \frac{ 1}{20} [/tex]
[tex]R_{ \:T} = 20 \: ohms[/tex]
From Ohm's law,
V = IR,
since 0.60A current passes through the 30 ohms resistor then the voltage across the 30 ohms
= 0.60 × 30
= 18 V.
Given that the resistors are arranged in parallel then same voltage is across the two resistors that is,
Voltage across 60 ohms = voltage across 30 ohms.
Voltage across 60 ohms = 18V